A bottler of drinking water fills plastic bottles with a mean volume of 993 milliliters (mL) and standard deviation of 4 mL. The
fill volumes are normally distributed. What proportion of bottles have volumes between 991 mL and 997 mL?
1 answer:
Answer:
52.38%
Step-by-step explanation:
P(991<X<997) = normalcdf(991,997,993,4) = 0.5328, therefore, about 52.38% of the bottles have volumes between 991 mL and 997 mL
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Answer:
PR=8; ST=5
Step-by-step explanation:
Find PR:
PQ=PR
8=2x
x=4
PR=2x=2(4)=8
Find ST:
TU=ST
2z+3=5z
3=3z
z=1
ST=5z=5(1)=5