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MAVERICK [17]
3 years ago
9

Find the Midpoint of the segment drawn between the two points

Mathematics
1 answer:
laila [671]3 years ago
6 0
Answer:

M = (1.5, 0.5)

Step-by-step explanation:

Use the midpoint formula to find the midpoint between two points

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I'd say that a 12 ounce feeder can feed about 40 hummingbirds
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Help me find Angle B
DENIUS [597]

Answer:

55 degrees

Step-by-step explanation:

180-95-30=55

6 0
3 years ago
What is the fraction eight twentieths in its simplest form?
Nostrana [21]
Both the numerator and denominator are divisible by 4, meaning that when they are both divided by this number they wll be in their simplest form.

e.g. 8/4=2 and 20/4=5

Therefore the simplest form is 2/5
7 0
3 years ago
A. 2 (2)(3)(3)(a)(a)(a)(a)(a)(a)(a)(a)3(3)(5)(5)(a)(a)
marishachu [46]

Answer:

  • E. 2/5 a³

Step-by-step explanation:

  • \sqrt{36a^8/225a^2} =                       simplify
  • \sqrt{4a^6/25} =                              square root
  • 2/5 a³

Also possible option is B if 4a⁶/25 is under root

8 0
2 years ago
Read 2 more answers
A sample of blood pressure measurements is taken for a group of adults, and those values (mm Hg) are listed below. The values ar
Kobotan [32]

Answer:

The coefficient of variation for the systolic measurements is 12.8 %

The coefficient of variation for the diastolic measurements is 16.3 %

Therefore, we can conclude that the systolic measurements are less dispersed as compared to diastolic measurements.

Step-by-step explanation:

The coefficient of variation is the ratio of standard deviation of the data to the mean of the data. It shows the dispersion in the data set.

Coefficient of variation for the systolic measurements:

Mean = μ = (120 + 128 + 156 + 98 + 154 + 122 + 118 + 136 + 128 + 120)/10

Mean = μ = 1280/10

Mean = μ = 128

Standard deviation = σ = \sqrt{\frac{1}{N}\sum_ (x-\mu)^{2} }

Using excel the standard deviation is found to be

Standard deviation = σ = 16.4

Coefficient of variation = σ/μ

Coefficient of variation = 16.4/128

Coefficient of variation = 0.128

Coefficient of variation = 12.8%

Coefficient of variation for the Diastolic measurements:

Mean = μ = (79 + 76 + 75 + 51 + 92 + 87 + 59 + 64 + 72 + 81)/10

Mean = μ = 736/10

Mean = μ = 73.6

Standard deviation = σ = \sqrt{\frac{1}{N}\sum_ (x-\mu)^{2} }

Using excel the standard deviation is found to be

Standard deviation = σ = 12

Coefficient of variation = σ/μ

Coefficient of variation = 12/73.6

Coefficient of variation = 0.163

Coefficient of variation = 16.3%

Conclusion:

We can conclude that the systolic measurements (12.8%) are less dispersed as compared to diastolic measurements (16.3%).

7 0
3 years ago
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