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3 years ago

Your friend diets and goes from 125 pounds to 110 pounds what was her percentage of weight loss

Mathematics

1 answer:

Bad White [126]3 years ago

4 0

Answer: 12%

<u>Step-by-step explanation:</u>

$\frac{New - Original}{Original}$

$\frac{110 - 125}{125}$

= $\frac{-15}{125}$

= -0.12

= 12% decrease

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Artemon [7]

Answer: x/3 = 18

Step-by-step explanation:

if x/3 is 18, then 18 - 7 = 11

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4 years ago

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4 years ago

Tell whether the ratios form a proportion. 14:8 and 28:10

Dima020 [189]

Answer:

Step-by-step explanation:

14:8 = 14/8 = 7/4

28:10 = 28/10 = 14/5

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2 years ago

Dilate a triangle with vertices (0,0), (0,2) and (2,0) using the scale factor k=3. What is the value of the ratio (new to origin

seropon [69]

Answer:

Part a) The ratio of the perimeters is $3$

Part b) The ratio of the areas is $9$

Step-by-step explanation:

Part A) What is the value of the ratio (new to original) of the perimeters?

we know that

If two figures are similar, then the ratio of its perimeters is equal to the scale factor

Let

z-----> the scale factor

x-----> the perimeter of the new triangle

y-----> the perimeter of the original triangle

$z=\frac{x}{y}$

we have

$z=3$

substitute

$\frac{x}{y}=3$

Part B) What is the value of the ratio (new to original) of the areas?

we know that

If two figures are similar, then the ratio of its areas is equal to the scale factor squared

Let

z-----> the scale factor

x-----> the area of the new triangle

y-----> the area of the original triangle

$z^{2}=\frac{x}{y}$

we have

$z=3$

substitute

$\frac{x}{y}=3^{2}$

$\frac{x}{y}=9}$

3 0

3 years ago

PLS HURRY Point S is translated 5 units to the left and 12 units up to create point S'. Find the distance between point S and po

svet-max [94.6K]

Given:

Point S is translated 5 units to the left and 12 units up to create point S'.

To find:

The distance between the points S and S'.

Solution:

Point S is translated 5 units to the left and 12 units up to create point S'.

The diagram for the given problem is shown below.

From the below figure it is clear that the distance between the point S and S' is the height of a right triangle whose legs are 5 units and 12 units.

By Pythagoras theorem,

$Hypotenuse^2=Perpendicular^2+Base^2$

$SS'^2=(12)^2+(5)^2$

$SS'^2=144+25$

$SS'^2=169$

Taking square root on both sides.

$SS'=\sqrt{169}$

$SS'=13$

Therefore, the distance between S and S' is 13 units.

8 0

3 years ago