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3 years ago

Which measure of central tendency best represents the most requested song at a radio station?

Mathematics

1 answer:

tamaranim1 [39]3 years ago

7 0

The mode because it is the number that occurs more often but in this situation it would be most requested song.

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Answer the question pictured to the right.

Norma-Jean [14]

You’re answer should be 9-7 hope this helped

3 0

3 years ago

Customer arrivals at a bank are random and independent; the probability of an arrival in any one-minute period is the same as th

IgorLugansk [536]

Answer:

0.2240418 ; 0.57681

Step-by-step explanation:

Given the information above :

A) What is the probability of exactly three arrivals in a one-minute period?

Using poisson probability function :

p(x ; m) = [(m^x) * (e^-m)] / x!

Here, m = mean = 3, x = 3

P(3 ; 3) = [(3^3) * (e^-3)] / 3!

P(3;3) = [27 * 0.0497870] / 6

= 1.3442508 / 6

= 0.2240418

B) What is the probability of at least three arrivals in a one-minute period?

Atleast 3 arrivals

X >= 3 = 1 - [p(0) + p(1) + p(2)]

P(0 ; 3) = [(3^0) * (e^-3)] / 0! = (1 * 0.0497870) / 1 = 0.0497870

P(1 ; 3) = [(3^1) * (e^-3)] / 1! = (3 * 0.0497870) / 1 = 0.1493612

P(2 ; 3) = [(3^2) * (e^-3)] / 2! = (9 * 0.0497870) / 2 = 0.2240418

1 - [0.0497870 + 0.1493612 + 0.2240418]

1 - 0.42319 = 0.57681

7 0

3 years ago

What is an equivalent ratio of 5:2

avanturin [10]

<span>an equivalent ratio of 5:2
= 10:4
= </span>15:6
= 20:8
= 25:10
= 30:12

8 0

3 years ago

Read 2 more answers

A person runs 1 4/5 miles in 1/5 of an hour determine how many miles they are running per hour

asambeis [7]

Multiply 1 4/5 by 5
9/5 * 5/1 = 45/5 = 9 miles

8 0

3 years ago

Read 2 more answers

According to the histogram of travel times to work from the US 2000 census (Page 6 of "Journey to Work: 2000"), roughly what per

erastovalidia [21]

Histograms are used to represent data, where the length of each bar represents the frequency of the data element

The histogram is not given; So, I will give a general explanation.

Assume that the number of commuters that travel more than 45 minutes is 450, while the total number of commuters surveyed is 500.

The percentage of commuters that travel more than 45 minutes is the quotient of the commuters that travel more than 45 minutes and the total number of surveyed commuters.

So, we have:

$\%Percentage = \frac{450}{500}$

Divide 450 by 500

$\%Percentage = 0.9$

Express as percentage

$\%Percentage = 90\%$

Hence, the percentage of commuters that travel more than 45 minutes is 90%