Suppose the number of 2 hours lessons are x and 1 hour lessons are y; thus,
2x+y=25
50x+30y=690
to get the values of x and y we solve the quadratic equation given;
from the top equation:
y=25-2x.......i
substituting i in our second equation we get:
50x+30(25-2x)=690
50x+750-60x=690
-10x=-60
thus;
x=6
hence we conclude that the number of 2 hours classes are 6 hours
Your equation would be y = 210x + 240
Each time you add a night, the price will go up by 210 so each night will have a common difference of 210. This eliminates options C and D.
Going back to the phrase I used "common difference" not "ratio," this tells you to use an arithmetic sequence.
Your answer should be option A if I'm not mistaken (haven't done arithmetic and geometric sequences in quite some time).
Answer:
Easy to produce, affordable, and abundant
Step-by-step explanation:
I literally just answered it
Answer:
c< 7
Step-by-step explanation:
the product of c and 7 is less than 49
Product means multiply
7c< 49
Divide each side by 7
7c/7 < 49/7
c< 7