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satela [25.4K]
3 years ago
10

Help with this please 

Mathematics
1 answer:
emmainna [20.7K]3 years ago
7 0
\bf \begin{array}{llll}
step~1&4x=28\\\\
step~2&x=\cfrac{28}{4}\impliedby \textit{she did not divide 28 by 4}
\end{array}

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Consider F and C below. F(x, y, z) = yz i + xz j + (xy + 6z) k C is the line segment from (2, 0, −2) to (5, 4, 2) (a) Find a fun
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Answer:

Required solution (a) f(x,y,z)=xyz+3z^2+C (b) 40.

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F(x,y,z)=yz \uvec i +xz\uvec j+(xy+6z)\uvex k

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F(x,y,z)=yz \uvec i +xz\uvec j+(xy+6z)\uvex k=f_x \uvec{i} +f_y \uvex{j}+f_z\uvec{k}

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compairinfg with f_y=xz of the given function we get,

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on compairing we get,

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\int_C \vec{F}.dr=\int_C \nabla f. d\vec{r}=f(5,4,2)-f(2,0,-2)=(52+C)-(12+C)=40

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