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satela [25.4K]
3 years ago
10

Help with this please 

Mathematics
1 answer:
emmainna [20.7K]3 years ago
7 0
\bf \begin{array}{llll}
step~1&4x=28\\\\
step~2&x=\cfrac{28}{4}\impliedby \textit{she did not divide 28 by 4}
\end{array}

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Ket [755]

<em>Answer:</em>

<em>Divide them all</em>

<em>Hope you like it!</em>

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The+pie+chart+shows+the+age+distribution+in+a+village+of+120+a)+how+many+people+are+older+than+60+=+120+B)+What+percentage+of+th
AleksandrR [38]

Answer:

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5 0
3 years ago
Find the coordinates of the other endpoint when you are given the midpoint (point M) and one of the endpoints (point P)
satela [25.4K]
The known endpoint is P = (-16,0)

Let Q = (x,y) be the other endpoint. It is unknown for now.

Looking at the x coordinates of P and Q, we see that they are -16 and x respectively. Adding these values up gives -16+x. Dividing that result by 2 gives (-16+x)/2. This result is exactly equal to the midpoint x coordinate, which is the x coordinate of M (0). 

So we have this equation (-16+x)/2 = 0. Let's solve for x

(-16+x)/2 = 0
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x-16+16 = 0+16
x = 16

Therefore the x coordinate of point Q is 16.

------------------------------------

Let's do something similar for the y coordinates.

The y coordinates of P and Q are 0 and y respectively. Add them up and divided by 2, then set the result equal to -16 (y coordinate of midpoint M) getting this equation (0+y)/2 = -16

Solve for y

(0+y)/2 = -16
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The y coordinate of point Q is -32

------------------------------------

The point Q goes from (x,y) to (16, -32)

Final Answer: (16, -32)
3 0
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What conclusions can you draw about the roots of the equation x^3+x^2-2x+12=0​
nexus9112 [7]

Answer:

x=-3

Step-by-step explanation:

If x=-3, then

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(x+3)(x²-2x+4)

((x²-2x+4) has no real roots)........

4 0
3 years ago
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