Answer:
We want to write an inequality with the points (3, 78), (0, 312) and (5, 10) as solutions.
Then the set of the x-values is {0, 3, 5}
The set of the y-values is {10. 78. 312}
So if we wrote an inequality like:
y > 5
It would include all these solutions, because:
10 > 5
78 > 5
312 > 5
And this has no restriction on the x-variable, so all the x-value range can be a solution, meaning that the points (3, 78), (0, 312) and (5, 10) are solutions to that inequality.
Another one (also trivial) can be:
x < 9
because:
3 < 9
0 < 9
5 < 9
And we have no restriction on the y-values, then the points (3, 78), (0, 312) and (5, 10) are solutions to that inequality.
Answer:
The unit vector u is (-5/√29) i - (2/√29) j
Step-by-step explanation:
* Lets revise the meaning of unit vector
- The unit vector is the vector ÷ the magnitude of the vector
- If the vector w = xi + yj
- Its magnitude IwI = √(x² + y²) ⇒ the length of the vector w
- The unit vector u in the direction of w is u = w/IwI
- The unit vector u = (xi + yj)/√(x² + y²)
- The unit vector u = [x/√(x² + y²)] i + [y/√(x² + y²)] j
* Now lets solve the problem
∵ v = -5i - 2j
∴ IvI = √[(-5)² +(-2)²] = √[25 + 4] = √29
- The unit vector u = v/IvI
∴ u = (-5i - 2j)/√29 ⇒ spilt the terms
∴ u = (-5/√29) i - (2/√29) j
* The unit vector u is (-5/√29) i - (2/√29) j
whatttttttt? i have no idea what that is
Answer:
5
Step-by-step explanation:
hope this helps ;)
