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AlekseyPX
3 years ago
5

On Monday, Jill used 12 quart of paint in 34 hour. On Tuesday, Jill was distracted by texting and used 12 quart of paint in 54 h

our. What is the difference in her usage rates in quarts per hour?
Mathematics
1 answer:
disa [49]3 years ago
6 0

Answer:

monday,12 quart paint=34hour

Tuesday,12quart paint=54 hour

54 hour_34hour=20 hour difference

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Tammy scored 88, 72, 44 points on her first three test. What must she score in her last test to get at least an average of 70?
lara [203]

Answer:

76

Step-by-step explanation:

(88+72+44+x)/4=70

88+72+44+x=280

204+x=280

x=76

Therefore, Tammy needs to score a 76 on her last test to get at least an average of 70.

5 0
2 years ago
After being treated with chemotherapy, the radius of the tumor decreased by 23%. What is the corresponding percentage decrease i
Crazy boy [7]

Answer:

The volume of the tumor experimented a decrease of 54.34 percent.

Step-by-step explanation:

Let suppose that tumor has an spherical geometry, whose volume (V) is calculated by:

V = \frac{4\pi}{3}\cdot R^{3}

Where R is the radius of the tumor.

The percentage decrease in the volume of the tumor (\%V) is expressed by:

\%V = \frac{\Delta V}{V_{o}} \times 100\,\%

Where:

\Delta V - Absolute decrease in the volume of the tumor.

V_{o} - Initial volume of the tumor.

The absolute decrease in the volume of the tumor is:

\Delta V = V_{o}-V_{f}

\Delta V = \frac{4\pi}{3}\cdot (R_{f}^{3}-R_{o}^{3})

The percentage decrease is finally simplified:

\%V = \left[1-\left(\frac{R_{f}}{R_{o}}\right)^{3} \right]\times 100\,\%

Given that R_{o} = R and R_{f} = 0.77\cdot R, the percentage decrease in the volume of tumor is:

\%V = \left[1-\left(\frac{0.77\cdot R}{R}\right)^{3} \right]\times 100\,\%

\%V = 54.34\,\%

The volume of the tumor experimented a decrease of 54.34 percent.

5 0
3 years ago
Could someone show me how to start this function in excel.
Mrac [35]
Attached is a screenshot of spreadsheet used to do this problem.

You will see the excel functions used for each column. The average score is highlighted in blue.

6 0
3 years ago
A right-angled triangle has shorter side lengths exactly c^2-b^2 and 2bc units respectively, where b and c are positive real num
yKpoI14uk [10]

Answer: hypotenuse = c^{2} + b^{2}

Step-by-step explanation: Pythagorean theorem states that square of hypotenuse (h) equals the sum of squares of each side (s_{1},s_{2}) of the right triangle, .i.e.:

h^{2} = s_{1}^{2} + s_{2}^{2}

In this question:

s_{1} = c^{2}-b^{2}

s_{2} = 2bc

Substituing and taking square root to find hypotenuse:

h=\sqrt{(c^{2}-b^{2})^{2}+(2bc)^{2}}

Calculating:

h=\sqrt{c^{4}+b^{4}-2b^{2}c^{2}+(4b^{2}c^{2})}

h=\sqrt{c^{4}+b^{4}+2b^{2}c^{2}}

c^{4}+b^{4}+2b^{2}c^{2} = (c^{2}+b^{2})^{2}, then:

h=\sqrt{(c^{2}+b^{2})^{2}}

h=(c^{2}+b^{2})

Hypotenuse for the right-angled triangle is h=(c^{2}+b^{2}) units

3 0
3 years ago
What is 2/7 as a decimal
Tamiku [17]
Its .2857142857(long decimal xD)
6 0
3 years ago
Read 2 more answers
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