Answer:
Let's define the cost of the cheaper game as X, and the cost of the pricer game as Y.
The total cost of both games is:
X + Y
We know that both games cost just above AED 80
Then:
X + Y > AED 80
From this, we want to prove that at least one of the games costed more than AED 40.
Now let's play with the possible prices of X, there are two possible cases:
X is larger than AED 40
X is equal to or smaller than AED 40.
If X is more than AED 40, then we have a game that costed more than AED 40.
If X is less than or equal to AED 40, then:
X ≥ AED 40
Now let's take the maximum value of X in this scenario, this is:
X = AED 40
Replacing this in the first inequality, we get:
X + Y > AED 80
Replacing the value of X we get:
AED 40 + Y > AED 80
Y > AED 80 - AED 40
Y > AED 40
So when X is equal or smaller than AED 40, the value of Y is larger than AED 40.
So we proven that in all the possible cases, at least one of the two games costs more than AED 40.
The answer is 49/9 because you can first convert the fraction into a decimal and devide 4 and 0.9 and you will get 5.4 repeating and which is 49/9
You basically have to find the slope, to find the average rate of change, because finding the slope and finding the average rate of change is basically the same thing.
Here's the formula :

So here, all you'd have to do is simply pick two points, and insert them into this formula. Say you take the points (-2, -2) and (0,-3). You would start from the y-intercept of the second point, and insert them all into the formula.
which would turn into
. And so since you want a good, stable number, and not just a fraction, you would divide -1 and 2, and the average rate of change would be
-0.50.
AVERAGE RATE OF CHANGE :
-0.50
Answer:

Step-by-step explanation:

Adjust based on LCM (15):



You change 120% into a decimal, 1.20
then you multiply 1.2 by 40
Answer: 48 cakes Fred will sell a day