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3 years ago

9

PLEASE HELP URGENT!!!!!!!

1 answer:

MrMuchimi3 years ago

4 0

Answer:

Choice B is correct

Step-by-step explanation:

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(8/9)^2 I need to evaluate this

tigry1 [53]

(8/9)^2 is just 8/9 squared, or 8/9 * 8/9. This is 64/81, and cannot be reduced. This is therefore our answer.

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3 years ago

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The area of the shaded region of the figure is _____ mm ²

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Answer:

400mm^2

Step-by-step explanation:

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3 years ago

The slope of the line that passes through the points (-10,y) and (5, 2) is 2/5. What is the value of y?

Murrr4er [49]

Answer:

C, -4

Step-by-step explanation:

slope=change in y/change in x

$\frac{2 - y}{5 - ( - 10)} = \frac{2}{5}$

$\frac{2 - y}{5 + 10} = \frac{2}{5}$

multiply both sides by 2/5

$2 - y = \frac{2}{5} (5 + 10)$

simplify the right side. 2/5 × 5 = 2 and 2/5 × 10 = 4

$2 - y = 2 + 4$

$2 - y = 6$

bring y to the other side by adding y on both sides

$2 = 6 + y$

subtract 6 on both sides

$2 - 6 = y$

so y is -4

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2 years ago

Estimate the product of 79.623 times 4.83

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It would be 384.58, or 384.57909

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3 years ago

You are looking at the New York ball drop on New Year’s Eve at a distance of 100 m away from the base of the structure. If the b

Fofino [41]

The question is an illustration of related rates.

The rate of change between you and the ball is 0.01 rad per second

I added an attachment to illustrate the given parameters.

The representations on the attachment are:

$\mathbf{x = 100\ m}$

$\mathbf{\frac{dy}{dt} = 2\ ms^{-1}}$ ---- the rate

$\mathbf{\theta = \frac{\pi}{4}}$

First, we calculate the vertical distance (y) using tangent ratio

$\mathbf{\tan(\theta) = \frac{y}{x}}$

Substitute 100 for x

$\mathbf{y = 100\tan(\theta) }$

$\mathbf{\tan(\theta) = \frac{y}{100}}$

Differentiate both sides with respect to time (t)

$\mathbf{ \sec^2(\theta) \cdot \frac{d\theta}{dt} = \frac{1}{100} \cdot \frac{dy}{dt}}$

Substitute values for the rates and $\mathbf{\theta }$

$\mathbf{ \sec^2(\pi/4) \cdot \frac{d\theta}{dt} = \frac{1}{100} \cdot 2}$

This gives

$\mathbf{ (\sqrt 2)^2 \cdot \frac{d\theta}{dt} = \frac{1}{100} \cdot 2}$

$\mathbf{ 2 \cdot \frac{d\theta}{dt} = \frac{1}{100} \cdot 2}$

Divide both sides by 2

$\mathbf{ \frac{d\theta}{dt} = \frac{1}{100} }$

$\mathbf{ \frac{d\theta}{dt} = 0.01 }$

Hence, the rate of change between you and the ball is 0.01 rad per second

Read more about related rates at:

brainly.com/question/16981791

8 0

2 years ago