Answer:
a-bi
Step-by-step explanation:
If a quadratic equation lx^2+mx+n=0 has one imaginary root as a+bi then the other root is the conjugate of a+bi = a-bi
Because we have l, m and n are real numbers and they are the coefficients.
Sum of roots = a+bi + second root = -m/l
When -m/l is real because the ratio of two real numbers, left side also has to be real.
Since bi is one imaginary term already there other root should have -bi in it so that the sum becomes real.
i.e. other root will be of the form c-bi for some real c.
Now product of roots = (a+bi)(c-bi) = n/l
Since right side is real, left side also must be real.
i.e.imaginary part =0
bi(a-c) =0
Or a =c
i.e. other root c-bi = a-bi
Hence proved.
Step-by-step explanation:
(3x-4y)×(3x-4y-(3x+4y))
(3x-4y)×(3x-4y-3x-4y)
(3x-4y)×(-8y)
-8y×(3x-4y
Answer:
the right answer is -5 (B)
Step-by-step explanation:
-(-5) +5(-5+2)
5 + -15 = -10
Answer:
QPT is obtuse
SPQ is acute
TPR is right
Step-by-step explanation:
Took geometry two years ago
Answer:
-1.2 that is the point hope this helps
Step-by-step explanation:
