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2 years ago

6

Solve it 6x+3y=15 x=2and y=5

1 answer:

Ghella [55]2 years ago

3 0

Step-by-step explanation:

$6x + 3y = 15x = 2and y = 5$

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Molly had a $12 gift card to download music. She bought 8 songs that each cost the same amount. Write a variable equation, then

inn [45]

Answer:

1.Equation ----- 8x=12

2. x=1.5

3. cost of a single song is $1.5

4.$12 gift card will download 8 songs

Step-by-step explanation:

The amount of money the gift card holds is $12

Number of songs bought= 8 songs

Let the cost of a single song to be =$x

The cost of 8 songs will be =$x × 8=$ 8x

So the 8 songs will all cost $12

This means; $ 8x = $12

Equation------ 8x=12

Finding cost of a single song

8x=12------------------divide by 8 both sides

x=12/8------------------simplify

x=3/2 = $ 1.5

Checking for solution

if a single song costs $1.5 , who many songs can a gift card with $12 download?

Here we divide $12 by $1.5 = $12/$1.5= 8 songs------------correct number of songs as mentioned in the question.

7 0

2 years ago

| -18 + 1| absolute value and helppplpllll

muminat

Answer:

17

Step-by-step explanation:

| -18 + 1|

-18 + 1 = -17

So,

| -17| = 17

This is because if | -a|, then | -a| = a

6 0

2 years ago

Read 2 more answers

Write an expression using an exponent to represent the

Ghella [55]

Answer: 4 to the power of 4

Step-by-step explanation: Adrian started of with $4 and by month 4 he will have 256. 4•4•4•4=256

3 0

2 years ago

Preston writes 3 songs in 2 days, working 7 hours each day. He spends the same amount of time on each song. How long does he spe

Alekssandra [29.7K]

Answer:

Step-by-step explanation:

In 2 days he spends 2*7 = 14 hours total

He divides the number of hours on each song evenly

14 /3 = 4 2/3 hours on each song.

What is 2/3 of an hour?

2/3 * 60 = 120 / 3 = 40 minutes

Total time spent on each song 4 hours and 40 minutes

5 0

2 years ago

Read 2 more answers

Consider the equation below. f(x) = 2x3 + 3x2 − 336x (a) Find the interval on which f is increasing. (Enter your answer in inter

Vaselesa [24]

We have been given a function $f(x)=2x^3+3x^2-336x$ . We are asked to find the interval on which function is increasing and decreasing.

(a). First of all, we will find the critical points of function by equating derivative with 0.

$f'(x)=2(3)x^{2}+3(2)x^1-336$

$f'(x)=6x^{2}+6x-336$

$6x^{2}+6x-336=0$

$x^{2}+x-56=0$

$x^{2}+8x-7x-56=0$

$(x+8)-7(x+8)=0$

$(x+8)(x-7)=0$

$x=-8,x=7$

So $x=-8,7$ are critical points and these will divide our function in 3 intervals $(-\infty,-8)U(-8,7)U(7,\infty)$ .

Now we will find derivative over each interval as:

$f'(x)=(x+8)(x-7)$

$f'(-9)=(-9+8)(-9-7)=(-1)(-16)=16$

Since $f'(9)>0$ , therefore, function is increasing on interval $(-\infty,-8)$ .

$f'(x)=(x+8)(x-7)$

$f'(1)=(1+8)(1-7)=(9)(-6)=-54$

Since $f'(1)$ , therefore, function is decreasing on interval $(-8,7)$ .

Let us check for the derivative at $x=8$ .

$f'(x)=(x+8)(x-7)$

$f'(8)=(8+8)(8-7)=(16)(1)=16$

Since $f'(8)>0$ , therefore, function is increasing on interval $(7,\infty)$ .

(b) Since $x=-8,7$ are critical points, so these will be either a maximum or minimum.

Let us find values of f(x) on these two points.

$f(-8)=2(-8)^3+3(-8)^2-336(-8)$

$f(-8)=1856$

$f(7)=2(7)^3+3(7)^2-336(7)$

$f(7)=-1519$

Therefore, $(-8,1856)$ is a local maximum and $(7,-1519)$ is a local minimum.

(c) To find inflection points, we need to check where 2nd derivative is equal to 0.

Let us find 2nd derivative.

$f''(x)=6(2)x^{1}+6$

$f''(x)=12x+6$

$12x+6=0$

$12x=-6$

$\frac{12x}{12}=-\frac{6}{12}$

$x=-\frac{1}{2}$

Therefore, $x=-\frac{1}{2}$ is an inflection point of given function.

3 0

2 years ago