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aleksley [76]
3 years ago
5

Twenty-Five Thousandth may be written....?

Mathematics
1 answer:
Greeley [361]3 years ago
3 0
It should be 0.025

None of the answers are correct
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What is the product?<br> 3x [-6 -11<br> 1-14 -9]
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Answer:

9.99

Step-by-step explanation:

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3 years ago
20 out of 50 rolls of a number cube resulted in a 2 being rolled.Based on this imformation, if the cube was rolled 220 times,how
jolli1 [7]

Answer:

88 rolls of 2.

Step-by-step explanation:

By proportion that would be 220 * 20/50

= 220 * 0.4

=  88.

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2 years ago
the function graphed shows kyoko's typing speed in words per minute (wpm) x weeks after she began typing course. How many words
Alinara [238K]

Answer:

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Step-by-step explanation:

4 0
3 years ago
One container is filled with mixture that is 25% acid. A second container is filled with a mixture that is 55% acid. The second
algol13

Answer:

Therefore the third container contains   \frac{735}{17}\% = 43.23 %  acid.

Step-by-step explanation:

Given that, One container is filled with the mixture that 25% acid. 55% acid is contain by second container.

Let the volume of first container be x cubic unit.

Since the volume of second container is 55% larger than the first.

Then the volume of the second container is

= (V\times \frac{100+55}{100})   cubic unit.

=\frac{155}{100}V  cubic unit.

The amount of acid in first container is

=V\times \frac{25}{100}  cubic unit.

=\frac{25}{100}V  cubic unit.

The amount of acid in second container is

=(\frac{155}{100}V \times \frac{55}{100}) cubic unit.

=\frac{8525}{10000}V cubic unit.

Total amount of acid =(\frac{25}{100}V+\frac{8525}{10000}V) cubic unit.

                                   =(\frac{2500+8525}{10000}V) cubic unit.

                                   =(\frac{11025}{10000}V)cubic unit.

Total volume of mixture =(V+\frac{155}{100}V) cubic unit.

                                       =\frac{100+155}{100}V cubic unit.

                                       =\frac{255}{100}V  cubic unit.

The amount of acid in the mixture is

=\frac{\textrm{The volume of acid}}{\textrm{The amount of mixture}}\times 100 \%

=\frac {\frac{11025}{10000}V}{\frac{255}{100}V}\times 100\%

=\frac{735}{17}\%

Therefore the third container contains  \frac{735}{17}\%  acid.

5 0
3 years ago
Solve the equation shown for x. 2/3 x -4 1/2 = -8
liq [111]
The answer would be -5 1/4
4 0
2 years ago
Read 2 more answers
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