$V=\dfrac{x^2*h}{3} =554.9\\\\x^2*h=554.9*3\\\\h=15.1\\\\x^2*15.1=554.9*3\\\\x^2=\dfrac{554.9*3}{15.1} \\\\x=\sqrt{\dfrac{1664,7}{15.1} } \\\\x=\sqrt{110,24503311258278145695364238411...} \\\\x=10,499763478887644993681148554978...\approx{10.50}$

8 0

3 years ago

Can you do 2 problems? and then someone else do the other 2 ty!

Lynna [10]

Answer:

5.) MIGHT I SAID MIGHT be 20+16+12=48km squared for perimeter and 192 (im not sure really) for area

i can only do one I HOPE this helps probably not tho

Step-by-step explanation:

6 0

3 years ago

A map's key shows that every 5 inches on the map represents 200 miles of actual distance Suppose the distance is 7 inches. What

zepelin [54]

280 mi
1 in= 40 mi

40x7=280 mi

8 0

3 years ago