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Leviafan [203]
3 years ago
5

4% of 73 is what ?????

Mathematics
1 answer:
kumpel [21]3 years ago
7 0
4% of 73 will be 2.92. 
<span>This is because 4/100 X 73 = 2.92 </span>
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Can someone help me with this 7th grade math
Ainat [17]

Answer:

for 7 fabric (square meters), he can make 2 cloaks. for 4 cloaks, he needs 14 fabric (square meters).

6 0
3 years ago
Carl is raising money for his football team. He is selling chocolate bars for $1.50 each and cookies for $2. He sold all 20 of h
stich3 [128]

Answer:

Carl has to sell at least 8 cookies.

c\geq 7.5

Step-by-step explanation:

Carl gets \$1.50 by selling 1 chocolate bar.

Earning from chocolate bars:

Total\ chocolate\ bar=20\\\\Earning\ from\ one\ chocolate\ bar=\$1.50\\\\Total\ earning\ from\ chocolate\ bar=Total\ chocolate\ bar\times cost\ of\ 1\ chocolate\ bar=20\times 1.5=\$30

Earning From cookies:

Let\ total\ number\ of\ cookies=c\\\\Cost\ of\ 1\ cookie=\$2\\\\Earning\ from\ cookies=2\times c=2c

Total\ earning=Earning\ from\ cookies+Earning\ from\ cookies+Earning\ from\ chocolate\ bars\\\\Total\ earning=30+2c

Carl wants to raise at least \$55

Total\ earning\geq 55\\\\2c+30\geq 55\\\\2c\geq 55-30\\\\2c\geq 15\\\\c\geq7.5

7 0
3 years ago
Original amount 120 and new amount is 30. what is the amount of decrease and percent of decrease
blagie [28]
0.04 i think im right hope this helps
4 0
3 years ago
Read 2 more answers
Heights (in centimeters) and weights (in kilograms) of 7 supermodels are given below. Find the regression equation, letting the
Delvig [45]
The regression equation:
y = m x + b
m = ( 57 - 50 ) / ( 178 - 168 ) = 7 / 10 = 0.7
50 = 0.7 * 168 + b
50 = 117.6 + b
b = 50 - 117.6
b = - 67.6
y = 0.7 * x - 67.6
The graph is in the attachment.
The weight of supermodel who is 171 cm tall:
y = 0.7 * 171 - 67.6 = 119.7 - 67.6 = 52.1 kg
Download docx
6 0
3 years ago
Two cars traveled equal distances in different amounts of time. Car A traveled the distance in 2.4 h, and Car B traveled the dis
Arte-miy333 [17]
One way to go about this is to first list everything we know in the form of variables. This will make it easier to see how these numbers correlate instead of trying to remember formulas to plug these numbers into.

TimeA = 2.4h (time of Car A to travel)
TimeB = 4h (time of Car B to travel)
SpeedA = SpeedB + 22mph (Speed of Car A<span>)
</span>SpeedB = SpeedA - 22mph (Speed of Car B<span>)
</span>Distance = x (the distance traveled by each car)

We are looking for SpeedA. How can we find this? Well, we know that speed multiplied by time is equal to distance, so let's start there.

SpeedA * 2.4h = x
<span>(SpeedB + 22mph) * 2.4h = x
</span>(2.4h * SpeedB) + 52.8miles = x

We also know that:
SpeedB * 4h = x

Since both of these equations are equal to x, we can combine them:
SpeedB * 4h = x = <span>(2.4h * SpeedB) + 52.8miles
</span>SpeedB * 4h = <span>(2.4h * SpeedB) + 52.8miles
</span>1.6h * Speed B = 52.8miles
SpeedB = 52.8/1.6 mph = 33 mph

<span>SpeedA = SpeedB + 22mph = 33mph + 22mph = 55mph
</span>
Therefore, Car A was traveling at 55mph.
3 0
3 years ago
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