a. Find the probability that an individual distance is
greater than 214.30 cm
We find for the value of z score using the formula:
z = (x – u) / s
z = (214.30 – 205) / 8.3
z = 1.12
Since we are looking for x > 214.30 cm, we use the
right tailed test to find for P at z = 1.12 from the tables:
P = 0.1314
b. Find the probability that the mean for 20 randomly
selected distances is greater than 202.80 cm
We find for the value of z score using the formula:
z = (x – u) / s
z = (202.80 – 205) / 8.3
z = -0.265
Since we are looking for x > 202.80 cm, we use the
right tailed test to find for P at z = -0.265 from the tables:
P = 0.6045
c. Why can the normal distribution be used in part (b),
even though the sample size does not exceed 30?
I believe this is because we are given the population
standard deviation sigma rather than the sample standard deviation. So we can
use the z test.
Answer:
idk
Step-by-step explanation:
You need to give the rugs dimensions in order to figure it out then plug them into a formula. The formula should be based on the rugs shape.
Steps to solve:
f(x) = 3x³ – 2x² + x; x = -3
~Substitute
f(-3) = 3(-3)³ - 2(-3)² + (-3)
~Solve the exponents
f(-3) = 3(-27) - 2(9) + (-3)
~Multiply
f(-3) = -81 - 18 - 3
~Subtract
f(-3) = -102
Best of Luck!
Answer:
The slope is zero. Since both coordinates have the y-value of -1, they are on the same line on the graph and form a horizontal line with a slope of zero. (a straight horizontal line)
Step-by-step explanation:
use the formula
(y2-y1)/(x2-x1)
to calculate the slope using 2 points
so where (x1,y1) (x2,y2) can be subsituted
so putting it in the formula ...
(-1-(-1))/(7-10)=
0/-3=0
Answer:
depending of the activity, learning subject, the hour or the class
Step-by-step explanation:
I am bore it seems that you are and thanks for the points :D