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3 years ago

Lines A, B, and C show proportional relationships. Which line has a constant of proportionality between y and x of 4/3

Mathematics

2 answers:

Drupady [299]3 years ago

8 0

Answer:

Line B

Give Brainliest plz

Charra [1.4K]3 years ago

8 0

line b would be your answer Give person on top Brainliest^^^

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3 years ago

What is the value of r?

finlep [7]

Answer:

A.12

Step-by-step explanation:

2×r-13 = 11

r + 2 = 14

11 + 14 = 25

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3 years ago

WILL GIVE 30 points a scatter plot and a possible line of best fit is shown is the line of best fit accurate for the data shown

mart [117]

It passes through the center of the points. (2)
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4 years ago

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What is the expression in radical form? (4x3y2)310

sertanlavr [38]

Given:

Consider the given expression is

$(4x^3y^2)^{\frac{3}{10}}$

To find:

The radical form of given expression.

Solution:

We have,

$(4x^3y^2)^{\frac{3}{10}}=(2^2)^{\frac{3}{10}}(x^3)^{\frac{3}{10}}(y^2)^{\frac{3}{10}}$

$(4x^3y^2)^{\frac{3}{10}}=(2)^{\frac{6}{10}}(x)^{\frac{9}{10}}(y)^{\frac{6}{10}}$

$(4x^3y^2)^{\frac{3}{10}}=(2)^{\frac{3}{5}}(x)^{\frac{9}{10}}(y)^{\frac{3}{5}}$

$(4x^3y^2)^{\frac{3}{10}}=\sqrt[5]{2^3}\sqrt[10]{x^9}\sqrt[5]{y^3}$ $[\because x^{\frac{1}{n}}=\sqrt[n]{x}]$

$(4x^3y^2)^{\frac{3}{10}}=\sqrt[5]{8y^3}\sqrt[10]{x^9}$ $[\because x^{\frac{1}{n}}=\sqrt[n]{x}]$

Therefore, the required radical form is $\sqrt[5]{8y^3}\sqrt[10]{x^9}$ .

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4 years ago

X=6 is a solution to the inequality x−5≤ 10 True or False?

vekshin1

Answer:

$\boxed{\sf{FALSE}}$

$\boxed{\sf{x\leq 15}}$

Step-by-step explanation:

Isolate the term of x from one side of the equation.

First, add by 5 from both sides.

$\sf{x-5+5\leq10+5}$

Solve.

Add the numbers from left to right.

$\sf{10+5=15}$

$\Longrightarrow: \boxed{\sf{x\leq 15}}$

Therefore, the solution is x≤15, which is our answer.

I hope this helps you! Let me know if my answer is wrong or not.

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2 years ago

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