The answer to your problem is 4.32.
The total surface area of the remaining solid is 48(4+✓3) centimeters square.
<h3>How to calculate the surface area?</h3>
Through a regular hexagonal prism whose base edge is 8 cm and the height is 12 cm, a hole in the shape of a right prism.
The formula for the total surface area will be:
= Total surface area=2(area of the base)+ parameter of base × height
where,
Height= 8cm
Parameter of base=12(2) = 24
Area of the base= 6×✓3/4×4² = 64✓3/4
The surface area of the remaining solid will be:
= 2(64✓3/4) + 24 × 8
= 2(64✓3/4 + 192
With the hole is a rhombus prism with the following parameters:
diagonal 1 = 6, diagonal 2 = 8, height = 12
The volume is:
V1 =0.5 × d1 × d2 × h
V1 = 0.5 × 6 × 8 × 12
V1 = 96
The dimensions of the hexagonal prism are:
Base edge (a) = 8
Height (h) = 12
The volume is
V2 = (3✓(3)/2)a²h
V2 = (3✓3)/2) × 8² × 12
V2 = 1152✓3
The remaining volume is
V = V2 -V1
V = 1152✓3 - 96
Learn more about the hexagonal prism on:
brainly.com/question/27127032
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What is the answer for what, please ask your question
Answer:
C
Step-by-step explanation:
3y - 5x = 15 ... A
y = 5/3 * X +15 .... slope 3/5 , y intercept 15
6y - 10x =30
(6y - 10x) /2 = 30 / 2
3y - 5x = 15 ... B
y = 5/3 * x + 15 ..... slope 3/5 , y intercept 15
∴ Answer is C
Answer: where is the quadrilateral
Step-by-step explanation:
