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2 years ago

13

Jane is making a suit that requires 2 5/8 yards for a jacket and 1 3/4 yards for a skirt. What is the total amount of material s

he needs?
A. 4 yards.
B. 4 3/8 yards.
C. 3 2/3 yards.
D. 3 1/2 yards

1 answer:

Delvig [45]2 years ago

3 0

The total amount of material she needs is 4 3/8 yards

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Use the least common denominator to write an equivalent fraction for each fraction. 2 6 , 7 8 The least common denominator is 24

seraphim [82]

Answer:

2/6 = 48/144

7/8 = 168/192

Step-by-step explanation:

Use the least common denominator to write an equivalent fraction for each fraction. 2/6 , 7/8 The least common denominator is 24 .

2/6 can be rewritten as __

We Multiply both numerator and Denominator by 24

48/144

7/8 can be rewritten as __

We Multiply both numerator and Denominator by 24

168/192

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3 years ago

Hepppppppplppppppplppppppppp

antoniya [11.8K]

Answer:

A = 3 ft, B = 7 ft, C = 4 ft, D = 5 ft, Surface Area = 96 ft^2

Step-by-step explanation:

<u>Step 1: Determine the sides</u>

A → 3 ft

B → 7 ft

C → 4 ft

D → 5 ft

<u>Step 2: Determine the surface area</u>

Area of the sides

$A= 4\ ft * 7\ ft = 28\ ft^2$

$A= 5\ ft * 7\ ft = 35\ ft^2$

$A= 3\ ft * 7\ ft = 21\ ft^2$

Area of the top and bottom triangles

$A= \frac{h\ *\ b}{2} = \frac{3\ ft\ *\ 4\ ft}{2} = \frac{12\ ft^2}{2} = 6\ ft^2 = 2(6\ ft^2) = 12\ ft^2$

Total Area

$28\ ft^2 + 35\ ft^2 + 21\ ft^2 + 12\ ft^2$

$96\ ft^2$

Answer: A = 3 ft, B = 7 ft, C = 4 ft, D = 5 ft, Surface Area = 96 ft^2

5 0

2 years ago

Read 2 more answers

Can you walk me through this problem i dont understand it AREA OF POLYGONS

Mamont248 [21]

The area of a paralellogram is bh

each dimention is multiplied by n
b turns to bn
h turns to hn

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3 years ago

You buy a house for $230,000. It appreciates at a rate

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Answer:

1,232,142

Step-by-step explanation:

bro just use a calculator

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2 years ago

Two customers went to a post office to buy postcards and large envelopes. Each postcard

astraxan [27]

The right answer is Option A.

Step-by-step explanation:

Let,

x be the postcards

y be the large envelops

According to given statement;

14x+5y=12 Eqn 1

10x+15y=24.80 Eqn 2

Multiplying Eqn 1 by 3;

$3(14x+5y=12)\\42x+15y=36\ \ \ Eqn \ 3$

Subtracting Eqn 2 from Eqn 3;

$(42x+15y)-(10x+15y)=36-24.80\\42x+15y-10x-15y=11.20\\32x=11.20\\$

Dividing both sides by 32

$\frac{32x}{32}=\frac{11.20}{32}\\x=0.35$

Putting x=0.35 in Eqn 1;

$14(0.35)+5y=12\\4.90+5y=12\\5y=12-4.90\\5y=7.10$

Dividing both sides by 5

$\frac{5y}{5}=\frac{7.10}{5}\\y=1.42$

Therefore, one large envelope costs $1.42

The right answer is Option A.

Keywords: linear equations, subtraction

Learn more about linear equations at:

#LearnwithBrainly

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3 years ago