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likoan [24]
3 years ago
14

Solve the inequality 4y + 3 > 2y + 14​

Mathematics
1 answer:
aleksley [76]3 years ago
6 0

9514 1404 393

Answer:

  y > 11/2

Step-by-step explanation:

Subtract 2y+3 to get the variable term alone on one side.

  2y > 11

  y > 11/2 . . . . . . divide by the coefficient of y

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velikii [3]
<h3>Answer: B) Experiment</h3>

Reason:

Whenever you have two groups like this, one labeled the treatment group and the other the control group, we have an experiment gong on.

The treatment group gets the actual medication that is being tested. The control group gets a fake medication, aka placebo. Usually a placebo is meant for humans because it's more of a psychological factor. With cats, it likely won't affect them. However, such practices of having two groups like this is standard no matter what group of subjects you're testing.

The idea is that if the treatment group has better results compared to the placebo group, then it's likely the medication works.

4 0
2 years ago
If one of the angels of a triangle is 127 it’s called
KonstantinChe [14]

Answer:

obtuse triangle

Step-by-step explanation:

only one angle in a triangle has to be over 90 degrees for it to be and obtuse triangle

hoped this helped

7 0
3 years ago
A soccer game lasts 90 minutes without running into overtime. The coach
KatRina [158]

Answer: 7 Switches will be made.

Step-by-step explanation:

\frac{90}{12.5}= number of switches

7.2= number of switches

  • however you cannot have a fraction of a switch so you must round it to a whole number, which in this case is 7.

5 0
2 years ago
The numbers​ 1, 2,​ 3, 4, and 5 are written on slips of​ paper, and 2 slips are drawn at random one at a time without replacemen
mamaluj [8]
<h2>Answer:</h2>

(a)

The probability is :  1/2

(b)

The probability is :  1/2

<h2>Step-by-step explanation:</h2>

The numbers​ 1, 2,​ 3, 4, and 5 are written on slips of​ paper, and 2 slips are drawn at random one at a time without replacement.

The total combinations that are possible are:

(1,2)   (1,3)    (1,4)    (1,5)

(2,1)   (2,3)   (2,4)   (2,5)

(3,1)   (3,2)   (3,4)   (3,5)

(4,1)   (4,2)   (4,3)   (4,5)

(5,1)   (5,2)   (5,3)   (5,4)

i.e. the total outcomes are : 20

(a)

Let A denote the event that the first number is 4.

and B denote the event that the sum is: 9.

Let P denote the probability of an event.

We are asked to find:

               P(A|B)

We know that it could be calculated by using the formula:

P(A|B)=\dfrac{P(A\bigcap B)}{P(B)}

Hence, based on the data we have:

P(A\bigcap B)=\dfrac{1}{20}

( Since, out of a total of 20 outcomes there is just one outcome which comes in A∩B and it is:  (4,5) )

and

P(B)=\dfrac{2}{20}

( since, there are just two outcomes such that the sum is: 9

(4,5) and (5,4) )

Hence, we have:

P(A|B)=\dfrac{\dfrac{1}{20}}{\dfrac{2}{20}}\\\\i.e.\\\\P(A|B)=\dfrac{1}{2}

(b)

Let A denote the event that the first number is 3.

and B denote the event that the sum is: 8.

Let P denote the probability of an event.

We are asked to find:

               P(A|B)

Hence, based on the data we have:

P(A\bigcap B)=\dfrac{1}{20}

( since, the only outcome out of 20 outcomes is:  (3,5) )

and

P(B)=\dfrac{2}{20}

( since, there are just two outcomes such that the sum is: 8

(3,5) and (5,3) )

Hence, we have:

P(A|B)=\dfrac{\dfrac{1}{20}}{\dfrac{2}{20}}\\\\i.e.\\\\P(A|B)=\dfrac{1}{2}

7 0
3 years ago
Pls help I’ll brainlest ASAP
Dmitry_Shevchenko [17]
Substract by 12 from 42, and keep going down until you hit -54, which is 8 hours!
4 0
3 years ago
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