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likoan [24]
3 years ago
14

Solve the inequality 4y + 3 > 2y + 14​

Mathematics
1 answer:
aleksley [76]3 years ago
6 0

9514 1404 393

Answer:

  y > 11/2

Step-by-step explanation:

Subtract 2y+3 to get the variable term alone on one side.

  2y > 11

  y > 11/2 . . . . . . divide by the coefficient of y

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If the length of the minor axis of an ellipse is 6 units and the length of the major axis is 10 units, how far from the center a
Sedbober [7]

The distance from the center to where the foci are located exists 8 units.

<h3>How to determine the distance from the center?</h3>

The formula associated with the focus of an ellipse exists given as;

c² = a² − b²

Where c exists the distance from the focus to the center.

a exists the distance from the center to a vertex,

the major axis exists 10 units.

b exists the distance from the center to a co-vertex, the minor axis exists 6 units

c² = a² − b²

c² = 10² - 6²

c² = 100 - 36

c² = 64

c = \sqrt{64}

c = 8

Therefore, the distance from the center to where the foci are located exists 8 units.

To learn more about the Pythagorean theorem here:

brainly.com/question/654982

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3 0
1 year ago
A school is having a valentine's day sale. The first day,they sold 20 roses and 15 boxes of chocolate for $80. The second day th
True [87]

Answer:

roses were $1 each and chocolates were $4 per box

Step-by-step explanation:

let Cost of 1 rose = "R" and Cost of 1 box of chocolate = "C"

First day: cost of 20 roses + cost of 15 chocolate = $80,

or...

20R + 15C = 80  (divide both sides by 5)

4R + 3C = 16 ------------(eq 1)

Second day: cost of 40 roses + cost of 20 chocolate = $120,

or...

40R + 20C = 120  (divide both sides by 10)

4R + 2C = 12 ------------(eq 2)

by elimination, (eq 1) - (eq 2)

(4R + 3C) - (4R + 2C) = 16 - 12

4R + 3C - 4R - 2C = 4

C = 4  (substitute this back into eq 1)

4R + 3(4) = 16

4R + 12 = 16

4R = 16 - 12

4R = 4

R = 1

Hence roses were $1 each and chocolates were $4 per box

5 0
3 years ago
Please help
Vlada [557]

We know that

When we have

f(x)=ax^2 +bx+c

Here ,

a is the leading coefficient

c is the constant term

so, we can compare it with

f(x)=5x^2-7x+6

so, we get

a=5,c=6

so,

leading coefficient is 5

constant term is 6......................Answer

4 0
4 years ago
Which of the following values has 3 significant figures?
laiz [17]

Answer: I believe that the answer is all of the above

Step-by-step explanation:

7 0
4 years ago
150pounds = what in kilograms
Minchanka [31]

this is your answer.

Answer: 68.0389

3 0
2 years ago
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