There are at least 3 houses on a street if at least two of them have addresses that are consecutive integers.
Using a system of equations, it is found that there are 5 dimes and 9 quarters in his pocket.
<h3>What is a system of equations?</h3>
A system of equations is when two or more variables are related, and equations are built to find the values of each variable.
In this problem, the variables are given as follows:
- Variable x: number of dimes in his pocket.
- Variable y: number of quarters in his pocket.
He has a total of 14 coins, hence:
x + y = 14 -> y = 14 - x.
They are worth $2.75, hence, considering the value of each coin(dimes $0.1 and quarters $0.25), we have that:
0.1x + 0.25y = 2.75
Since y = 14 - x:
0.1x + 0.25(14 - x) = 2.75
x = (0.25*14 - 2.75)/0.15.
x = 5.
y = 14 - x = 14 - 5 = 9.
There are 5 dimes and 9 quarters in his pocket.
More can be learned about a system of equations at brainly.com/question/24342899
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Answer:
dont use this
Step-by-step explanation:
oinf+euiv=4
Answer:
You are correct
Step-by-step explanation:
Start with 1 1/2. This can be made into an improper fraction which is 3/2
Now multiply both top and bottom of 3/2 by 5
(3*5)/(2 * 5) = 15 / 10
16/10 is just slightly bigger than 15/10
Answer:
Graphed?
Step-by-step explanation: