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ivann1987 [24]
3 years ago
15

There are 17 students participating in a spelling bee. how many ways can the students who go first and second be chosen?

Mathematics
1 answer:
Karo-lina-s [1.5K]3 years ago
5 0
With 17 students there’s 17 possibilities for anyone to go first
For second, a person can’t be firsts and second so there is 16 possibilities for someone to go second

17*16=272

There’s 272 ways that the students who go first and second are chosen
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If 2k, 5k-1 and 6k+2 are the first 3 terms of an arithmetic sequence, find k and the 8th term​
Klio2033 [76]

Answer:

see explanation

Step-by-step explanation:

The common difference d of an arithmetic sequence is

d = a_{2} - a_{1} = a_{3} - a_{2}

Substitute in values and solve for k, that is

5k - 1 - 2k = 6k + 2 - (5k - 1)

3k - 1 = 6k + 2 - 5k + 1

3k - 1 = k + 3 ( subtract k from both sides )

2k - 1 = 3 ( add 1 to both sides )

2k = 4 ⇒ k = 2

--------------------------------------------------------

The n th term of an arithmetic sequence is

a_{n} = a_{1} + (n - 1)d

a_{1} = 2k = 2 × 2 = 4 and

d = 5k - 1 - 2k = 3k - 1 = (3 × 2) - 1 = 5

Hence

a_{8} = 4 + (7 × 5) = 4 + 35 = 39

4 0
3 years ago
what is your name? your age ? and then if you are 12 or 13 can you call me i need help on computer science i will give you my ph
ch4aika [34]
Oop- I’ll pass on telling you everything about me :/
8 0
3 years ago
Read 2 more answers
Anyoneee?? Mean Median and mode
juin [17]

Answer:

mode is the most occuring number which is in this case 11

you get the median by putting them in order from least to greatest and them marking them out until you get to the middle but if there are two numbers in the middle you add them and then divide by two and that is your median but in this case your median is 11

you get the mean by adding all the numbers together and dividing by how many numbers there are so in this case you are dividing by 9 and when you add oall of these numbers together you get 98 and 98/9 is 10.8888888889 which you would round and get 10.9

hope this helps

3 0
2 years ago
Help due today please ​
horsena [70]

Answer:

<em>angle ABD =</em><u><em>55 degree</em></u>

<em>angle BCD= </em><u><em>125 degree</em></u>

Step-by-step explanation:

angle ABD and angle DBC are supplementary angles.

Hence, angle ABD +angle DBC = 180 --equation 1

angle ABD = (2x+15) ---equation 2

angle BCD = (4x+45) ------equation 3

ABD+DBC=180

(2x+15) + ( 4x+45 ) = 180

2x+4x+15+45=180

6x+60=180

6x=180-60

6x=120

x=120/6=20

angle ABD= 2x+15= 2(20) +15

                              =40+15= 55 degree

angle BCD= 4x+45 = 4(20) +45

                                = 80+45= 125 degree

Hence, angle ABD =55 degree

            angle BCD= 125 degree

<em>Hope this helps.</em>

7 0
3 years ago
Math question 2! Thanks if you help
Greeley [361]

Answer: 15.6 m

Step-by-step explanation:

Two legs of right angle in right triangle given are 12m and 10m.

For the third side use Pythagoras theorem:

C^2= a^2+b^2

C=√[(12^2)+(10^2)]

C=√[144+100]

C=√[244]= 15.6 m

6 0
3 years ago
Read 2 more answers
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