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Mrrafil [7]
3 years ago
6

Solve y over negative 4 + 5 = 15. 80 −80 40 −40

Mathematics
1 answer:
Virty [35]3 years ago
8 0
The answer is - 40. Observe.

y/-4 + 5 = 15
y = -40 
-40/-4 = 10
10 + 5 = 15 

Thus, y= -40
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Use special right triangles to solve for the exact value of x. 4 16 9
maks197457 [2]

CHECK THE ATTACHMENT FOR THE FIGURE OF THE QUESTIONS

Answer:

Option A. is correct x = 4

Step-by-step explanation:

From the given figure

The adjacent of the given right angle triangle is

8 units which is the base,

Then x units is the opposite of the right angle triangle which is the height.

The hypotenuse side also has x units

Then value of x is required,

But going by right angle triangle trigonometry

cos(x) = adjacent / hypotenuse

Where adjacent= 8 unit

cos( 60) = 8/x

1/2 = 8/x

x = 8/2

= 4unit

Hence, Option A is correct, with 4 units

6 0
3 years ago
Can someone help me please?
anzhelika [568]

Answer:

1. y ax

|
A-------------------------------B

|

------------C---------------------

|

|__________________x ax

for this, your A might be (0,5), B (5,5), C (2,2).

parallel means railroad tracks: same slope, different intercepts.

line AB in this case has a slope of 0, intercept (0,5), so y₁=0x+5 or just y₁=5

the line passing through C also has slope 0, but intercept (0,2), so y₂=0x+2 or just y₂=2

2. perpendicular means that the slopes of two lines multiply out to -1. If line AB has, for example, a slope of 2/3, then the line passing through C would have slope -3/2 (negative reciprocal). To make things easier have either point A or B be on the x or y axis

khan academy has some helpful videos :)

https://www.khanacademy.org/math/geometry/hs-geo-analytic-geometry/hs-geo-parallel-perpendicular-eq/v/perpendicular-lines

3 0
2 years ago
Find value of P and Q
ch4aika [34]

Answer:

P= 6 \frac{1}{7}\\\\Q = 4 \frac{2}{7}

Step-by-step Explanation

\frac{5 + 3 \sqrt{2} }{5 - 3 \sqrt{2} }  = P+Q\sqrt 2 \\  \\  \frac{(5 + 3 \sqrt{2}) }{(5 - 3 \sqrt{2}) }  \times  \frac{(5 + 3 \sqrt{2}) }{(5   +  3 \sqrt{2} )} = P+Q\sqrt 2 \\  \\  \frac{ {(5 + 3 \sqrt{2} )}^{2} }{ {(5)}^{2}  - (3 \sqrt{2})^{2}  }  = P+Q\sqrt 2 \\  \\ \frac{ {5}^{2} +  {(3 \sqrt{2} )^{2}  + 2.5.3 \sqrt{2} } }{25 - 9 \times 2} = P+Q\sqrt 2 \\  \\\frac{ 25 + 18  + 30 \sqrt{2}  }{25 - 18} = P+Q\sqrt 2 \\  \\\frac{ 43  + 30 \sqrt{2}  }{7} = P+Q\sqrt 2 \\  \\ \frac{43}{7}  +  \frac{30 }{7} \sqrt{2}  = P+Q\sqrt 2 \\  \\ equating \: like \: terms \: on \: both \: sides \\  \\ P =  \frac{43}{7}   \\  \\ \huge \red { \boxed{ P= 6 \frac{1}{7}}}  \\  \\ Q =  \frac{30}{7}  \\  \\ \huge  \orange { \boxed{ Q = 4 \frac{2}{7} }}

4 0
3 years ago
Show ur work and check it for both
Oksi-84 [34.3K]

Answer:

7) is 26 8) is 20

30-4=26

16+4=20

5 0
3 years ago
Whats is the square root of 2 multiply by one over the square root of 2
Ket [755]

When ANY number is multiplied by its own reciprocal, the product is ' 1 '.

8 0
4 years ago
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