All categories

2 years ago

Which expression is equivalent to 5a+20?

Mathematics

2 answers:

abruzzese [7]2 years ago

8 0

Answer: 5(a+4)

Step-by-step explanation:

andriy [413]2 years ago

8 0

An expression that is equivalent to 5a + 20 is: 5 ( a + 4 ).

Since 5 times a equals 5a and 5 times 4 equals 20.

Therefore, 5 (a + 4) is equivalent to 5a + 20.

You might be interested in

Dear branily, Don't delete MY question/answer WITHOUT LOOKING at it first. Why is it so hard just for you to look at the questio

viva [34]

Answer:

Volume measures how much water (for example) can fit in an object

I don't know what the other questions mean

I can edit my answer if you can explain cuz these questions don't really make sense since these are all methods of measurement

Step-by-step explanation:

4 0

2 years ago

Plz solve!!!!! I will give 25 points and brainliest!! and plz, no tiny links 1 3/7*2/5

Airida [17]

Answer:

10/7*2/5= 20/35=4/7

5 0

2 years ago

Read 2 more answers

What value of y makes the 2 triangles congruent by SSS?

aleksandrvk [35]

The triangle was just flipped so the missing side is going to equal 36, so...
2y+20= 36
(Subtract 20 from each side to isolate the 2y)
2y= 16
(Divide each side by 2 to isolate the variable)

ANSWER:
y= 8

8 0

3 years ago

What is the largest possible integral value in the domain of the real-valued function

kotegsom [21]

Answer:

Max Value: x = 400

General Formulas and Concepts:

Algebra I

Domain is the set of x-values that can be inputted into function f(x)

Calculus

Antiderivatives
Integral Property: $\int {cf(x)} \, dx = c\int {f(x)} \, dx$
Integration Method: U-Substitution
[Integration] Reverse Power Rule: $\int {x^n} \, dx = \frac{x^{n+1}}{n+1} + C$

Step-by-step explanation:

Step 1: Define

$f(x) = \frac{1}{\sqrt{800-2x} }$

Step 2: Identify Variables

Using U-Substitution, we set variables in order to integrate.

$u = 800-2x\\du = -2dx$

Step 3: Integrate

Define: $\int {f(x)} \, dx$
Substitute: $\int {\frac{1}{\sqrt{800-2x} } } \, dx$
[Integral] Int Property: $-\frac{1}{2} \int {\frac{-2}{\sqrt{800-2x} } } \, dx$
[Integral] U-Sub: $-\frac{1}{2} \int {\frac{1}{\sqrt{u} } } \, du$
[Integral] Rewrite: $-\frac{1}{2} \int {u^{-\frac{1}{2} }} \, du$
[Integral - Evaluate] Reverse Power Rule: $-\frac{1}{2}(2\sqrt{u}) + C$
Simplify: $-\sqrt{u} + C$
Back-Substitute: $-\sqrt{800-2x} + C$
Factor: $-\sqrt{-2(x - 400)} + C$

Step 4: Identify Domain

We know from a real number line that we cannot have imaginary numbers. Therefore, we cannot have any negatives under the square root.

Our domain for our integrated function would then have to be (-∞, 400]. Anything past 400 would give us an imaginary number.

7 0

3 years ago

Question 7

Eddi Din [679]

Answer:

Step-by-step explanation:

New height to initial height=

10/4=2.5

New width from initial width should be 5×2.5=12.5inches

4 0

3 years ago