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valentina_108 [34]
2 years ago
10

Which expression is equivalent to 5a+20?

Mathematics
2 answers:
abruzzese [7]2 years ago
8 0

Answer: 5(a+4)

Step-by-step explanation:

andriy [413]2 years ago
8 0

An expression that is equivalent to 5a + 20 is: 5 ( a + 4 ).

Since 5 times a equals 5a and 5 times 4 equals 20.

Therefore, 5 (a + 4) is equivalent to 5a + 20.

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viva [34]

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Step-by-step explanation:

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Airida [17]

Answer:

10/7*2/5= 20/35=4/7

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What value of y makes the 2 triangles congruent by SSS?
aleksandrvk [35]
The triangle was just flipped so the missing side is going to equal 36, so...
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ANSWER:
y= 8
8 0
3 years ago
What is the largest possible integral value in the domain of the real-valued function
kotegsom [21]

Answer:

Max Value: x = 400

General Formulas and Concepts:

<u>Algebra I</u>

  • Domain is the set of x-values that can be inputted into function f(x)

<u>Calculus</u>

  • Antiderivatives
  • Integral Property: \int {cf(x)} \, dx = c\int {f(x)} \, dx
  • Integration Method: U-Substitution
  • [Integration] Reverse Power Rule: \int {x^n} \, dx = \frac{x^{n+1}}{n+1} + C

Step-by-step explanation:

<u>Step 1: Define</u>

f(x) = \frac{1}{\sqrt{800-2x} }

<u>Step 2: Identify Variables</u>

<em>Using U-Substitution, we set variables in order to integrate.</em>

u = 800-2x\\du = -2dx

<u>Step 3: Integrate</u>

  1. Define:                                                                                                            \int {f(x)} \, dx
  2. Substitute:                                                                                         \int {\frac{1}{\sqrt{800-2x} } } \, dx
  3. [Integral] Int Property:                                                                                     -\frac{1}{2} \int {\frac{-2}{\sqrt{800-2x} } } \, dx
  4. [Integral] U-Sub:                                                                                           -\frac{1}{2} \int {\frac{1}{\sqrt{u} } } \, du
  5. [Integral] Rewrite:                                                                                          -\frac{1}{2} \int {u^{-\frac{1}{2} }} \, du
  6. [Integral - Evaluate] Reverse Power Rule:                                                 -\frac{1}{2}(2\sqrt{u}) + C
  7. Simplify:                                                                                                         -\sqrt{u} + C
  8. Back-Substitute:                                                                                            -\sqrt{800-2x} + C
  9. Factor:                                                                                                           -\sqrt{-2(x - 400)} + C

<u>Step 4: Identify Domain</u>

We know from a real number line that we cannot have imaginary numbers. Therefore, we cannot have any negatives under the square root.

Our domain for our integrated function would then have to be (-∞, 400]. Anything past 400 would give us an imaginary number.

7 0
3 years ago
Question 7
Eddi Din [679]

Answer:

Step-by-step explanation:

New height to initial height=

10/4=2.5

New width from initial width should be 5×2.5=12.5inches

4 0
3 years ago
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