Identify the natural number that is closest to 4–√. 2 3 1 4

Using the numbers 8, 6, 4, and 2 write an expression that equals 32.

Dennis_Churaev [7]

One way can be 8x(6-4+2).

4 0

3 years ago

(Distribute , then simplify the remaining expression. Final answer must be in standard form) Please help !!

Sergeu [11.5K]

Problem 22
$4x^2(2x^2+x-5) - x(x^3+5x^2-3) + 17$
$4x^2(2x^2)+4x^2(x)+4x^2(-5) - x(x^3)-x(5x^2)-x(-3) + 17$
$8x^4+4x^3-20x^2 - x^4-5x^3+3x + 17$
$7x^4-x^3-20x^2+3x + 17$

So the final simplified answer to problem 22 is
$7x^4-x^3-20x^2+3x + 17$

--------------------------------

Problem 23
$-2x(x^3-6x^2+6)+4x^3-(5x^4+10x)$
$-2x(x^3)-2x(-6x^2)-2x(6)+4x^3-(5x^4)-(10x)$
$-2x^4+12x^3-12x+4x^3-5x^4-10x$
$-7x^4+16x^3-22x$

So problem 23 simplifies to
$-7x^4+16x^3-22x$

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Problem 24
$4b[2a^2-5(3ab-2b^2)]+29ab^2$
$4b[2a^2-5(3ab)-5(-2b^2)]+29ab^2$
$4b[2a^2-15ab+10b^2]+29ab^2$
$4b[2a^2]+4b[-15ab]+4b[10b^2]+29ab^2$
$8a^2b-60ab^2+40b^3+29ab^2$
$8a^2b-31ab^2+40b^3$

So problem 24 simplifies to
$8a^2b-31ab^2+40b^3$

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Problem 25
$2y(6x-4x^2y)+13x^2y^2-6$
$2y(6x)+2y(-4x^2y)+13x^2y^2-6$
$12xy-8x^2y^2+13x^2y^2-6$
$12xy+5x^2y^2-6$

The final answer for problem 25 is
$12xy+5x^2y^2-6$

8 0

3 years ago

public accountant financial planner 50.2 48.0 59.8 49.2 57.3 53.1 59.2 55.9 53.2 51.9 56.0 53.6 49.9 49.7 58.5 53.9 56.0 52.8 51

ddd [48]

Using the formula of test statistic, the value of the test statistic is 2.6961.

The mean of the public accountant is

Mean x(p) =50.2+59.8+57.3+59.2+53.2+56.0+49.9+58.5+56.0+51.9/10

x(p) = 55.2

Now the standard deviation of public accountant is

SD(p) = √{∑(x-x(p))^2/n-1}

SD(p) = √(50.2-55.2)^2+(59.8-55.2)^2+..................+(51.9-55.2)^2/n-1

After solving;

SD(p) = 3.34

The mean of the financial planner is

Mean x(F) =48.0+49.2+53.1+55.9+51.9+53.6+49.7+53.9+52.8+48.9/10

x(F) = 51.6

Now the standard deviation of financial planner is

SD(F) = √{∑(x-x(p))^2/n-1}

SD(F) = √(48.0-51.6)^2+(49.2-51.6)^2+..................+(48.9-51.6)^2/n-1

After solving;

SD(F) = 2.57

Test Statistic (t) = $\frac{x(P)-x(f)}{\sqrt{\left(\frac{(n(p)-1)s(p)^2+(n(f)-1)s(f)^2}{n(p)+n(f)-2}\left(\frac{1}{n(p)}+\frac{1}{n(f)}\right)\right)}}$

t = $\frac{55.2-51.61}{\sqrt{\left(\frac{(10-1)(3.34))^2+(10-1)(2.57)^2}{10+10-2}\left(\frac{1}{10}+\frac{1}{10}\right)\right)}}$

After solving

t = 2.6961

Hence, the value of the test statistic is 2.6961.

To learn more about test statistic link is here

brainly.com/question/14128303

#SPJ4

The right question is

public accountant 50.2 59.8 57.3 59.2 53.2 56.0 49.9 58.5 56.0 51.9

financial planner 48.0 49.2 53.1 55.9 51.9 53.6 49.7 53.9 52.8 48.9

Use a 0.05 level of significance and test the hypothesis that there is no difference between the starting annual salaries of public accountants and financial planner

Find the value of the test statistic.

4 0

10 months ago

what are the mean variacne and standard deviatioon of the values? round to the nerates tenth. 11,11,3,1,11

alexdok [17]

Answer:

Mean = 8

Variance = 22

Standard deviation = 4.6904

Step-by-step explanation:

To find out Mean the formula is : total sum of data set / number of values

(11 + 11 + 3 + 1 + 11 + 11) / 6 = 48 / 6 = 8

Mean = 8

Now for variance we will form a table

x 11 11 3 1 11 11

(x - Mean) 3 3 -5 -7 3 3

(x - Mean)² 9 9 25 49 9 9

Now we the formula of variance =

Variance = (9+9+25+49+9+9)/(6-1) = 110/5 = 22

Variance = 22

Now we know Standard deviation = √(variance)

Therefore standard deviation = √22 = 4.6904

Hope this helps!<3

4 0

1 year ago

Read 2 more answers

A merchant has 120 litres and 180 litres of two kinds of oil. He wants to sell the oil by filing the two kinds of equal volumes.

ANEK [815]

Answer:

HCF of 120 and 180 is 60 and hence a measuring tin of 60 litre volume should be bought.

3 0

2 years ago