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3 years ago

Identify the natural number that is closest to 4–√. 2 3 1 4

Mathematics

1 answer:

Minchanka [31]3 years ago

7 0

I think the result are 1 and 4

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What is the solution to -4(8 - 3x)2 6x - 8?

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Answer:

1) -32+12x 2) 2(3x-4)

Step-by-step explanation:

I hope this is right!

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Identify the x-intercepts of the function below f(x)=x^2+12x+24

damaskus [11]

<u>ANSWER: </u>

x-intercepts of $\mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})$

<u>SOLUTION:</u>

Given, $f(x)=x^{2}+12 x+24$ -- eqn 1

x-intercepts of the function are the points where function touches the x-axis, which means they are zeroes of the function.

Now, let us find the zeroes using quadratic formula for f(x) = 0.

$X=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Here, for (1) a = 1, b= 12 and c = 24

$X=\frac{-(12) \pm \sqrt{(12)^{2}-4 \times 1 \times 24}}{2 \times 1}$

$\begin{array}{l}{X=\frac{-12 \pm \sqrt{144-96}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{48}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{16 \times 3}}{2}} \\\\ {X=\frac{-12 \pm 4 \sqrt{3}}{2}} \\ {X=\frac{2(-6+2 \sqrt{3})}{2}, \frac{2(-6-2 \sqrt{3})}{2}} \\\\ {X=(-6+2 \sqrt{3}),(-6-2 \sqrt{3})}\end{array}$

Hence the x-intercepts of $\mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})$

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3 years ago

What is the slope of (-5,3) and (7,9)

Softa [21]

Answer:

-35

___

Step-by-step explanation:

Start by setting up your pairs (x,y)

-5 & 7 are x

3 & 9 are y

X * X

---------- ÷

Y * Y

(-5, 7)

---------

(3, 9)

-35

-------

3 0

3 years ago