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zhuklara [117]
4 years ago
6

A rectangle has length 3 feet and width 1/4 foot. What is the area of the rectangle?

Mathematics
1 answer:
Lera25 [3.4K]4 years ago
5 0
Area=width*length\\\\length=3ft\\width=\frac{1}{4}ft\\\\ Area=3*\frac{1}{4}=\frac{3}{4}ft^2\\\\Area\ of\ rectangle\ is\ equal\ to\ \frac{3}{4}ft^2.
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Find the coordinates of quadrilateral PQRS with vertices P(1, 4), Q(-1, 4), R(-2, -4) and S(2, -4) under the translation (x,y)--
Georgia [21]
We apply the rule to each of the vertices:
 (x, y) ---> (x-5, y + 3)
 P (1,4) ---> (1-5,4 + 3) >> (-4, 7)
 Q (-1,4) ---> (-1-5,4 + 3) >> (-6, 7)
 R (-2, -4) ---> (-2-5, -4 + 3) >> (- 7, -1)
 S (2, -4) ---> (2-5, -4 + 3) >> (-3, -1)
 Answer:
<span> a.
 P’(-4, 7), Q’(-6, 7) , R’(-7, -1) and S’(-3, -1)</span>
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3 years ago
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Bogdan [553]

Answer:

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7 0
3 years ago
Read 2 more answers
If cot theta = -2, find the value of cot theta + cot (theta -pi) + cot (theta-2pi)
nika2105 [10]

Given:

\cot \theta = -2

To find:

The value of \cot \theta +\cot (\theta -\pi)+\cot(\theta -2\pi).

Solution:

We know that,

\cot (\theta -n\pi)=\cot \theta         ...(i)

Where n is an integer.

We have,

\cot \theta +\cot (\theta -\pi)+\cot(\theta -2\pi)

Using (i), it can be written as

\cot \theta +\cot (\theta -\pi)+\cot(\theta -2\pi)=\cot \theta +\cot \theta +\cot \theta

\cot \theta +\cot (\theta -\pi)+\cot(\theta -2\pi)=3\cot \theta

It is given that \cot \theta = -2.

\cot \theta +\cot (\theta -\pi)+\cot(\theta -2\pi)=3(-2)

\cot \theta +\cot (\theta -\pi)+\cot(\theta -2\pi)=-6

Therefore, the value of the given function expression is -6.

6 0
3 years ago
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3 years ago
Suppose f(x) = x^2 and g(x) = (1/4)^2. Which statement best compares the graph of g(x) with the graph of f(x)
hjlf

Answer:

g(x) is the image of f(x) after stretched horizontally by scale factor = 4

Step-by-step explanation:

The statement that best compares the graph of  g(x) with the graph of f(x) says g(x) is the image of f(x) after stretched horizontally by scale factor = 4 because:

Given the function

f(x) = x²  and g(x) = (1/4x)² the image of f(x) after one transformation.  

The transformation shows that g(x) stretches away from y-axis.  

Since the transformation is stretched horizontally. So g(x) is the image of f(x) after stretched horizontally by scale factor (I.e. by 1).

Then we use the scale factor to divide g(x)

1 ÷ ¼ = 1 x 4/1 = 4  

So therefore, g(x) is the image of f(x) after stretched horizontally by scale factor = 4

8 0
4 years ago
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