Answer:
C. H0: PL - PR = 0
Ha: PL - PR > 0
The null hypothesis for this case is that left-handed pitchers in a baseball league are not more likely to strike out batters than right-handed pitchers are. That is the proportion of at-bats resulting in a strikeout is significantly equal for both left-handed and right-handed pitchers.
H0: PL - PR = 0
The alternative hypothesis is that the proportion of at-bats resulting in a strikeout is significantly higher for left-handed pitchers
Ha: PL - PR > 0
PL - proportion of at-bats resulting in a strikeout for left-handed pitchers
PR - proportion of at-bats resulting in a strikeout for right-handed pitchers
Step-by-step explanation:
The null hypothesis (H0) tries to show that no significant variation exists between variables or that a single variable is no different than its mean. While an alternative Hypothesis (Ha) attempt to prove that a new theory is true rather than the old one. That a variable is significantly different from the mean.
The null hypothesis for this case is that left-handed pitchers in a baseball league are not more likely to strike out batters than right-handed pitchers are. That is the proportion of at-bats resulting in a strikeout is significantly equal for both left-handed and right-handed pitchers.
H0: PL - PR = 0
The alternative hypothesis is that the proportion of at-bats resulting in a strikeout is significantly higher for left-handed pitchers
Ha: PL - PR > 0
PL - proportion of at-bats resulting in a strikeout for left-handed pitchers
PR - proportion of at-bats resulting in a strikeout for right-handed pitchers
The lateral area of the shape is the sum of the area of all lateral faces.
The area of the lateral face that is rectangle with sides 5 mi and 2 mi is
As you can see the shape has all four lateral faces of the same rectangular form with the same sides lengths, therefore,
Answer: correct choice is B.
If the width of the cardboard = x cm then its length is given by x + 8 cm.
Then the length of the box will be x + 8 - 2(2) = x + 4
and the width = x - 2(2) = x - 4 cm The height is 2 cm
Volume = h*w*l = 2(x - 4)(x + 4) = 256
2(x^2 - 16) = 256
x^2 - 16 = 128
x^2 = 144
x = 12 cm
Dimensions of the box are:-
length = 12 + 4 = 16cm
width = 12 - 4 = 8 cm
height = 2 cm
