There are different kinds of math problem. There will be 11 rats in sewer #1.
<h3>What are word problem?</h3>
The term word problems is known to be problems that are associated with a story, math, etc. They are known to often vary in terms of technicality.
Lets take
sewer #1 = a
sewer #2 = b
sewer #3 = c
Note that A=B-9
So then you would have:
A=B-9
B=C- 5
A+B+C=56
Then you have to do a substitution so as to find C:
(B- 9) + (C-5) + C = 56
{ (C- 5)-9} + (C-5) + C = 56
3C - 19 = 56
3C = 75
B = C- 5
B = 25 - 5
Therefore, B = 20
A = B - 9
= 25 - 9
=11
Therefore, there are are 11 rats in sewer #1
Learn more about Word Problems from
brainly.com/question/21405634
Answer:
-13
Step-by-step explanation:
-13
Answer: ASA method must be applied to the given triangles to prove then congruent.
In two triangles, if two angles and their included side are congruent then the two triangles are said to be congruent .This method is known as Angle-Side -Angle postulate(ASA).
In the given triangles one side with their corresponding angles are equal. Therefore by ASA postulate they are congruent.
There we can see no other sides are given equal therefore all the other options cannot be applied.
you are lucky I had this test yesterday and I have the answer is ASA my math teacher said it was fine
Answer:
2x - 0.4x ;
8x/5 ;
Yes
Step-by-step explanation:
Let number of miles = x
Arlene:
Double number of miles = 2 * x = 2x
Subtract 20% of the result :
2x - 20% of 2x ;
2x - 0.4x
Raul:
Divides Number of miles by 5 ; x / 5
Multiplies result by 8 ;
8 * (x/5) = 8x /5
To know if expressions are equivalent :
Let x = 10 miles
Using Arlene's expression:
2x - 0.4x
x = 10
2(10) - 0.4(10) = 16
Using Raul's expression :
8x / 5
(8*10) / 5
80/5
= 16
Since they give the same result, we can conclude that the expression are equivalent
