You want to find the area left over after the pool is built, so subtract the area of the pool from the area of the yard.
Area of Yard= Base x Height = 14x*19x = 266x^2
Area of Circle= Pi x Radius^2 = (6x)^2*pi = 36x^2*pi
Now subtract the two areas:
266x^2-(36^2*pi)
266x^2-36x^2*pi
Take 2x^2 as a common factor:
2x^2(133-18pi)
D: <span>2x^2(133-18pi)
Hope this helps :)</span>
Answer:
arturo earned the ,most
Step-by-step explanation:
Answer:
5.3
Step-by-step explanation:
You use the Pythagoras theorem which is a^2+b^2=c^2.
Since you're solving for a side length that's not the hypotenuse you will manipulate the equation to c^2-a^2=b^2. From here you just plug in numbers.
8^2 - 6^2 = b^2
64 - 36 = b^2
b = sqrt(28)
b = 5.2915.... = 5.3
Answer:
-4
Step-by-step explanation:
The slope of a line given two points is given by
m = (y2-y1)/(x2-x1)
= (-4-8)/(2 - -1)
= (-4-8)/(2+1)
= -12/3
= -4
No it’s not the square root of 32 is 5.65685424949
