Answer:
(7,6)
Step-by-step explanation:
Triangle ABC with vertices at points A(4,10), B(10, 10) , and C(10, 2) is a right triangle with the hypotenuse AC.
The circumcenter of the right triangle is the midpoint of the hypotenuse.
Find the coordinates of the midpoint O of the hypotenuse AC:
So, O(7,6)
Answer:
y = 3(x+1)^2 - 4
Step-by-step explanation:The general form of the equation of a quadratic function whose vertex is (h,k) and whose leading coefficient is a is:
y - k = a(x-h)^2, or
y = a(x-h)^2 - k
Substituting the coefficients of the vertex (-1, -4), we get:
y = a(x + 1)^2 - 4
Substituting the coordinates of the given point, (1,8), we get:
8 = a(1+1)^2 - 4, which simplifies to:
8 = a(2)^2 - 4, or
8 = 4a - 4. Then 4a = 12, and a = 3.
Thus, the desired equation is y = 3(x+1)^2 - 4 (answer j).
Answer:
c(4) = -76
Step-by-step explanation:
c(x) x=4 so plug 4 in for x
-5(4)² + (4)
Do parentheses first so... 4² = 16
-5(16) + 4
-5(16) = -80
-80+4 = -76
c(4) = -76
Answer:
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Step-by-step explanation:
