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Marrrta [24]
3 years ago
7

I need help on this problem ASAP!!

Mathematics
1 answer:
lianna [129]3 years ago
5 0
I believe the answer is J.

Sorry if its wrong
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What is the inverse of y=x^3
jolli1 [7]

The asnwer is:

3^X=y

you wern't specific in options so i took it literal

3 0
3 years ago
Divide,<br> 7)16.52 -<br><br> PLEASE ANSWER QUICK
Sedaia [141]

Answer:

0.42347247428

Step-by-step explanation:

my calcuator

7/16.52

8 0
3 years ago
Read 2 more answers
Which is the LCM of (x + y) and (x + y)2.​
Semmy [17]

Answer:

(x+y)²

Step-by-step explanation:

Given the expressions (x + y) and (x + y)².​

We are to find the LCM of (x + y) and (x + y)²

Taking the factors as shown

(x+y ) || (x + y) (x + y)²

(x+y ) || 1   (x+y)

        ||  1     1

Multiplying both factors to get the LCM

= (x+y)(x+y)

= (x+y)²

<em>Hence the LCM of (x + y) and (x + y)² is  (x+y)²</em>

8 0
3 years ago
Please help logarithms!
nlexa [21]

Given:

\log_34\approx 1.262

\log_37\approx 1.771

To find:

The value of \log_3\left(\dfrac{4}{49}\right).

Solution:

We have,

\log_34\approx 1.262

\log_37\approx 1.771

Using properties of log, we get

\log_3\left(\dfrac{4}{49}\right)=\log_34-\log_349      \left[\because \log_a\dfrac{m}{n}=\log_am-\log_an\right]

\log_3\left(\dfrac{4}{49}\right)=\log_34-\log_37^2      

\log_3\left(\dfrac{4}{49}\right)=\log_34-2\log_37          [\log x^n=n\log x]

Substitute \log_34\approx 1.262 and \log_37\approx 1.771.

\log_3\left(\dfrac{4}{49}\right)=1.262-2(1.771)

\log_3\left(\dfrac{4}{49}\right)=1.262-3.542

\log_3\left(\dfrac{4}{49}\right)=-2.28

Therefore, the value of \log_3\left(\dfrac{4}{49}\right) is -2.28.

5 0
3 years ago
|x + 3|&lt;7 whats the answers
Ksivusya [100]

Answer:

<em>x∈ -10,4</em>

Step-by-step explanation:

x+3<7, x+3≥0: -(x+3)<7, x+3<0- separate the inequality into 2 possible cases

x<4, x≥-3; x>-10, x<-3- solve the inequalities

x∈ [-3,4}; x∈ {-10,-3}- find the intersection

x∈{-10,4}- Find the union

4 0
4 years ago
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