All categories

3 years ago

67 oz =-----lb-----oz

Mathematics

1 answer:

vazorg [7]3 years ago

3 0

For this case we must do a conversion:

We have to by definition:

1 ounce equals 0.0625 pounds

Making a rule of three we have:

1 oz ------------> 0.0625 lb

67 oz ----------> x

Where "x" represents the number of equivalent pounds:

$x = \frac {67 * 0.0625} {1}\\x = 4.1875$

Thus, 67 ounces equals 4.1875 pounds

Answer:

67 ounces equals 4.1875 pounds

You might be interested in

Please help thanks! Brainliest <br> Sorry for spamming.

Bad White [126]

Answer: −10

Step-by-step explanation: 9^2−21/−6

81−21/−6

60/−6

−10

6 0

2 years ago

Determine if the following infinite series converges or diverges

Mandarinka [93]

Using limits, it is found that the infinite sequence converges, as the limit does not go to infinity.

<h3>How do we verify if a sequence converges of diverges?</h3>

Suppose an infinity sequence defined by:

$\sum_{k = 0}^{\infty} f(k)$

Then we have to calculate the following limit:

$\lim_{k \rightarrow \infty} f(k)$

If the <u>limit goes to infinity</u>, the sequence diverges, otherwise it converges.

In this problem, the function that defines the sequence is:

$f(k) = \frac{k^3}{k^4 + 10}$

Hence the limit is:

$\lim_{k \rightarrow \infty} f(k) = \lim_{k \rightarrow \infty} \frac{k^3}{k^4 + 10} = \lim_{k \rightarrow \infty} \frac{k^3}{k^4} = \lim_{k \rightarrow \infty} \frac{1}{k} = \frac{1}{\infty} = 0$

Hence, the infinite sequence converges, as the limit does not go to infinity.

More can be learned about convergent sequences at brainly.com/question/6635869

#SPJ1

6 0

1 year ago

Read 2 more answers

The expression 15 n + 5 n + 5 Which is another way to write this expression?

bixtya [17]

Answer:

cbdkkdfn

Step-by-step explanation:

bfnsowifnccvl

4 0

3 years ago

Read 2 more answers

A semicircle has the radius of 2 4/5. What is its area? leave your answers in term of π

Ratling [72]

Answer:

$11\dfrac{13}{25}\pi$

Step-by-step explanation:

r = Radius of semicircle = $2\dfrac{4}{5}=\dfrac{24}{5}\ \text{units}$

Area of semicircle is given by

$A=\dfrac{\pi r^2}{2}\\\Rightarrow A=\dfrac{\pi \left(\dfrac{24}{5}\right)^2}{2}\\\Rightarrow A=\dfrac{288}{25}\pi=11\dfrac{13}{25}\pi\ \text{sq. units}$

The area of the semicircle is $11\dfrac{13}{25}\pi\ \text{sq. units}$ .

4 0

2 years ago

What is the discriminate?

weqwewe [10]

So it’s basically asking for the difference

4 0

2 years ago