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Orlov [11]
3 years ago
6

Modrater give me answerif 2x- 35273 = 5361925 than find the value of 1x ​

Mathematics
2 answers:
Firlakuza [10]3 years ago
5 0

\displaystyle\ 2x-35273=5361925\\\\2x=53\underline{61925}+\underline{35273} \\\\2x=5397198\\\\\\x=\frac{5397198}{2} =2698599\\\\\underline{x=2698599\qquad }\\\\2\cdot 2698599-35273=5361925\\\\5397198-35273=5361925\\\\5361925=5361925

Nutka1998 [239]3 years ago
4 0

Answer:

2x - 35273 = 5361925 \\ 2x = 5361925 + 35273 \\ 2x = 5397198 \\ x =  \frac{5397198}{2}  \\ x = 2698599

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if in the study of the lifetime of 60-watt light bulbs it was desired to have a margin of error no larger than 6 hours with 99%
Dahasolnce [82]

The question is incomplete! Complete question along with answer and step by step explanation is provided below.

Question:

The lifetime (in hours) of a 60-watt light bulb is a random variable that has a Normal distribution with σ = 30 hours. A random sample of 25 bulbs put on test produced a sample mean lifetime of = 1038 hours.

If in the study of the lifetime of 60-watt light bulbs it was desired to have a margin of error no larger than 6 hours with 99% confidence, how many randomly selected 60-watt light bulbs should be tested to achieve this result?

Given Information:

standard deviation = σ = 30 hours

confidence level = 99%

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Required Information:

sample size = n = ?

Answer:

sample size = n ≈ 165

Step-by-step explanation:

We know that margin of error is given by

Margin of error = z*(σ/√n)

Where z is the corresponding confidence level score, σ is the standard deviation and n is the sample size

√n = z*σ/Margin of error

squaring both sides

n = (z*σ/Margin of error)²

For 99% confidence level the z-score is 2.576

n = (2.576*30/6)²

n = 164.73

since number of bulbs cannot be in fraction so rounding off yields

n ≈ 165

Therefore, a sample size of 165 bulbs is needed to ensure a margin of error not greater than 6 hours.

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