Answer:
True: B, C and D
Step-by-step explanation:
The graph of the function is shown in the attached diagram.
The vertex of the parabola (parabola is the graph of the function f(x)) is at (-3,-16), because
So, option A is false and option B is true.
As you can see from the graph, the function is increasing for all x>-3, thus option C is true.
The graph is positive for x<-7 and x>1 and negative for -7<x<1, so option D is true and option E is false.
Answer:
y = 11
Step-by-step explanation:
We use the definition of Supplementary Angles and Adjacent Angles.
Step 1: Set up equation 1 (Definition of Supplementary Angles)
5x - 4 +7x - 8 = 180
Step 2: Solve for <em>x</em>
12x - 4 - 8 = 180
12x - 12 = 180
12x = 192
x = 16
Step 3: Plug in <em>x</em>
5(16) - 4
80 - 4
76°
Step 4: Set up equation 2 (Definition of Supplementary Angles)
76 + 9y + 5 = 180
Step 5: Solve for <em>y</em>
9y + 81 = 180
9y = 99
y = 11
2, (double) 4, (double) 8 (double) 16, So 16 in week 4
2+4+8+16 = 30
After solving for both variables, you find that each bus can hold 59 students and each van can hold 18 students.
Step-by-step explanation:
You can find the amount of students each vehicle can carry by representing the two scenarios in equations.
You are trying to find how many students will fit in each bus or van, so the two variables used will be "b" to represent how many students can fit in a bus and "v" to represent how many students can fit in a van.
High school A used 1 van and 6 buses, so there will be 1"v" and 6"b" for 372 students.
High school B used 4 vans and 12 buses, so there will be 4"v" and 12"b" for 780 students.
Now, represent these in equations:
We can use substitution to solve this system:
can be rewritten as after subtracting 6b from both sides. You can then substitute this new value of "v" into the other equation to solve for "b":
After solving for b, you can then substitute the new value of b into the other equation to find the value of v:
After solving for both variables, you find that each bus can hold 59 students and each van can hold 18 students.
Area is height time width, or in this case, 3(2x^2+3x+5), which is 6x^2+9x+15.