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3 years ago

Pls help i will give brainliest

Mathematics

1 answer:

pshichka [43]3 years ago

4 0

Answer:

Try ABECFDGHI

Step-by-step explanation:

Im going FROM left to right

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Which is a true statement about any two chords that are the same distance from the center of a circle?

stepladder [879]

If two cords are the same distance from the center of a circle than both cords are congruent

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3 years ago

Read 2 more answers

Simplify. -4(3 – 1) +2

vladimir2022 [97]

Answer:

-4(3-1)+2

-4x2+2

-8+2= -6

since there is only one - and one + the answer will be negative

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3 years ago

Given right triangle ABC with altitude BD drawn to hypotenuse AC. If AC =16 and DC=5 what is the length of BC in the simplest ra

Nana76 [90]

The length of BC is $4 \sqrt{5}$ .

Solution:

Given ABC is a right triangle.

AC is the hypotenuse and BD is the altitude.

AB and BC are legs of the triangle ABC.

AC = 16 and DC = 5

Leg rule of geometric mean theorem:

$\frac{\text { hypotenuse }}{\text { leg }}=\frac{\text { leg }}{\text { part }}$

$\Rightarrow \frac{AC}{BC}=\frac{BC}{DC}$

$\Rightarrow \frac{16}{x}=\frac{x}{5}$

Do cross multiplication.

$\Rightarrow 16\times 5 = x\times x$

$\Rightarrow 80= x^2$

$\Rightarrow 16\times 5= x^2$

Taking square root on both sides.

$\Rightarrow \sqrt{16\times 5} = \sqrt{x^2}$

$\Rightarrow \sqrt{4^2\times 5} = \sqrt{x^2}$

square and square roots get canceled, we get

$\Rightarrow 4\sqrt{ 5} = x$

The length of BC is $4 \sqrt{5}$ .

7 0

3 years ago

Hey can you please help me posted picture of question

Elan Coil [88]

The correct answer is A.

Horizontal shift is obtained by addition/subtraction a number to every occurrence of x in the equation. Addition indicates a shift towards left and subtraction indicates a shift towards right.

So the correct answer is Subtract that number From.

4 0

3 years ago

HELP HELP HELP HELP ME!!!!!!!!!!!!!!!

leonid [27]

Answer:

$l=\frac{A-\frac{1}{2} \pi w^2}{2w}$

Step-by-step explanation:

We essentially need to solve for l; in other words, we must isolate it to one side.

First, notice that the term $\frac{1}{2} \pi w^2$ doesn't have any l terms in it, so we can just move this to the left side by subtracting both sides by $\frac{1}{2} \pi w^2$ :

A - $\frac{1}{2} \pi w^2$ = 2lw

Now, the right side has 2lw, so we must divide both sides by 2w to isolate l:

$l=\frac{A-\frac{1}{2} \pi w^2}{2w}$

~ an aesthetics lover

4 0

2 years ago