In lowest terms the answer would be 8 1/3
For this case we have the following equation:
h = -16t ^ (2) + 30t + 6
We substitute the value of h = 10 in the equation:
10 = -16t ^ (2) + 30t + 6
Rewriting we have:
0 = -16t ^ (2) + 30t + 6-10
0 = - 16t ^ (2) + 30t - 4
We look for the roots of the polynomial:
t1 = 0.144463904
t2 = 1.730536096
"the ball passes its maximum height, it comes down and then goes into the hoop". Therefore, the correct root is:
t = 1.730536096
Answer:
It goes into the hoop after:
t = 1.73 seconds
<span>To find f(2), plug in 2 for x. f(2) = 11
To find g(2), plug in 2 for x. g(2) = 2
To find (f o g) (2), plug in 2 for the composite function = 11.
To find (g o f) (2) plug in 2 for the composite function = 29.
g(f(x)) is when you plug in f(x) into g: 3(5x+1) - 4 = 15x - 1.
f(g(x)) is when you plug in g(x) into f: 5(3x-4) + 1 = 15x -19.</span>
Answer:
X intercept(s)= (19/5,0)
Y intercept(s)=(0,-19/11)
Step-by-step explanation:
