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NNADVOKAT [17]
3 years ago
11

I posted a question similar to this but I entered it wrong too many times :(

Mathematics
2 answers:
Murrr4er [49]3 years ago
8 0

umm sorry, my sister did this and I don't know how to remove it so I just add this note I am sorry so much again I am sorry...

slava [35]3 years ago
5 0

Answer:

\sqrt[4]{\frac{5}{7} }

Step-by-step explanation:

^4√5/^4√7

~Apply radical rules

^4√5/7

Best of Luck!

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According to a study, an average of six cell phone thefts is reported in San Francisco per day. Assume that the number of report
lions [1.4K]

Answer:0.29

Step-by-step explanation:

An average of six cell phone thefts is reported in San Francisco per day. This means our mean value, u = 6

For poisson distribution,

P(x=r) = (e^-u×u^r)/r!

probability that four cell phones will be reported stolen tomorrow=

P(x=4)= (e^-6×6^4)/4!

= (0.00248×1296)/4×3×2×1

= 3.21408/24=

0.13392

P(x=5)= (e^-6×6^5)/5!

= (0.00248×7776)/5×4×3×2×1

= 19.28448/120

= 0.1607

probability that four or five cell phones will be reported stolen tomorrow

= P(x=4) + P(x=5)

= 0.13392 + 0.1607

= 0.294624

Approximately 0.29

8 0
2 years ago
20 points for this make sure u explain
arsen [322]

Answer:

it literally says +10

Step-by-step explanation:

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6 0
3 years ago
Read 2 more answers
10^5 =<br><br>easy question​
Gennadij [26K]

Answer:

10^5 = 100000

Step-by-step explanation:

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4 0
2 years ago
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Use inductive reasoning to describe the pattern. Then find the next two numbers in the pattern. 1, 4, 7, 10, . . .
Kisachek [45]

Option a: add 3 to the previous term; 13, 16

Explanation:

The sequence is 1, 4, 7, 10, ....

We need to determine the next two terms of the sequence.

Hence to find the next two terms, first we shall find the common difference between every two terms.

Common difference between 1 and 4 = 4-1=3

Similarly, common difference between 4 and 7 = 7-4=3

Common difference between 7 and 10 = 10-7=3

Hence, the common difference is 3.

So, the next two terms will also have the same common difference 3.

To determine the next two terms, first we shall add 3 to the term 10, we get,

10+3=13

Similarly, adding 3 to the term 13, we get,

13+3=16

Thus, the sequence is 1, 4, 7, 10, 13, 16, .....

Thus, add 3 to the previous term; 13, 16

Hence, option a is the correct answer.

6 0
3 years ago
1. Consider the following hypotheses:
Andrej [43]

Answer:

See deductions below

Step-by-step explanation:

1)

a) p(y)∧q(y) for some y (Existencial instantiation to H1)

b) q(y) for some y (Simplification of a))

c) q(y) → r(y) for all y (Universal instatiation to H2)

d) r(y) for some y (Modus Ponens using b and c)

e) p(y) for some y (Simplification of a)

f) p(y)∧r(y) for some y (Conjunction of d) and e))

g) ∃x (p(x) ∧ r(x)) (Existencial generalization of f)

2)

a) ¬C(x) → ¬A(x) for all x (Universal instatiation of H1)

b) A(x) for some x (Existencial instatiation of H3)

c) ¬(¬C(x)) for some x (Modus Tollens using a and b)

d) C(x) for some x (Double negation of c)

e) A(x) → ∀y B(y) for all x (Universal instantiation of H2)

f)  ∀y B(y) (Modus ponens using b and e)

g) B(y) for all y (Universal instantiation of f)

h) B(x)∧C(x) for some x (Conjunction of g and d, selecting y=x on g)

i) ∃x (B(x) ∧ C(x)) (Existencial generalization of h)

3) We will prove that this formula leads to a contradiction.

a) ∀y (P (x, y) ↔ ¬P (y, y)) for some x (Existencial instatiation of hypothesis)

b) P (x, y) ↔ ¬P (y, y) for some x, and for all y (Universal instantiation of a)

c) P (x, x) ↔ ¬P (x, x) (Take y=x in b)

But c) is a contradiction (for example, using truth tables). Hence the formula is not satisfiable.

7 0
3 years ago
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