Answer:
6 chocolates
Step-by-step explanation:
If there was 2 chocolates left and he had just eaten a third that would mean he had eaten 1
That would mean there would have been three chocolates before he put away the groceries
Double that to make up for the chocolates eaten during the walk home = 6
<span><span>56 $ .... 7 hours of work
<span>x $
... 1 hour of work</span>
<span>We would
like to know how much money does Alexander's job pay per one hour (x $). You can calculate this in the following way:</span>
56 * 1 = 7 * x<span> /7</span>
x
= 56/7
x
= 8 $
<span>The
result is 8 $.</span></span></span>
Answer:
Uh, 2400%, I think? I think my answer might be incorrect
Answer: option 2 describes best
Step-by-step explanation:Given Marisol grouped the terms and factored the GCF out of the groups of the polynomial 6x3 – 22x2 – 9x + 33. Her work is shown.
Step 1: (6x3 – 22x2) – (9x + 33)
Step 2: 2x2(3x – 11) – 3(3x + 11)
Marisol noticed that she does not have a common factor. Which accurately describes what Marisol should do next?
Marisol should realize that her work shows that the polynomial is prime.
Marisol should go back and group the terms in Step 1 as (6x3 – 22x2) – (9x – 33).
Marisol should go back and group the terms in Step 1 as (6x3 – 22x2) + (9x – 33).
Marisol should refactor the expression in Step 2 as 2x2(3x + 11) – 3(3x + 11).
According to question Marisol grouped the terms and has done factorisation of the given polynomial 6x^3 – 22x^2 – 9x + 33.
In step 1 she has written as (6x^3 – 22x^2) – (9x + 33)
Marisol has to go to step 1 in order to correct her mistake. She has to group the expression as (6x^3 – 22x^2) – (9x – 33) so that she will be able to get the expression as
6x^3 – 22x^2 – 9x + 33 after opening the brackets.