Answer:
2.5 years
Step-by-step explanation:
Interest= P×R×T÷100
T= 100I÷P×R
T= 100×400÷8000×2
T= 40000÷16000
T= 5÷2
T= 2.5 years
The longest possible altitude of the third altitude (if it is a positive integer) is 83.
According to statement
Let h is the length of third altitude
Let a, b, and c be the sides corresponding to the altitudes of length 12, 14, and h.
From Area of triangle
A = 1/2*B*H
Substitute the values in it
A = 1/2*a*12
a = 2A / 12 -(1)
Then
A = 1/2*b*14
b = 2A / 14 -(2)
Then
A = 1/2*c*h
c = 2A / h -(3)
Now, we will use the triangle inequalities:
2A/12 < 2A/14 + 2A/h
Solve it and get
h<84
2A/14 < 2A/12 + 2A/h
Solve it and get
h > -84
2A/h < 2A/12 + 2A/14
Solve it and get
h > 6.46
From all the three inequalities we get:
6.46<h<84
So, the longest possible altitude of the third altitude (if it is a positive integer) is 83.
Learn more about TRIANGLE here brainly.com/question/2217700
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Answer:
D.
Step-by-step explanation:
So the question is asking which set of inequalities and given point represent the graph. The point it gives is (-3,1) on the graph. That already narrows your choices down to B and D. Now, the easiest way to see the answer is look at the y axis. In the equation y=mx+b, b is the value on the y axis. We see on the y axis that the equations pass through positive 1 and 2. D adds 1 and 2 the equations, so it would produce that graph.
Answer:
6a-18
Step-by-step explanation:
