Question

Find the force a 68.5 kg person would experience while standing on the surface of Mars. Mars has a mass of 6.43 x 1023 kg and a radius of 3.43 x 106m from its center to the surface.

Answer 1

F = Gm1m2/r^2 = 6.67 x 10^-11 * 68.5 * 6.43 x 10^23 / (3.43 x 10^6)^2 = 2.93 x 10^15 / 1.18 x 10^13 = 249.7N

Answer 2

Answer: The correct answer is F=249.82N.

Step-by-step explanation:

The expression for the gravitational force is as follows:

$F=\frac{GMm}{r^{2}}$

Here, M, m are the masses, G is the universal gravitational constant and r is the distance between masses.

It is given in the problem that a person having mass 68.5 kg experience a force while standing on the surface of mars.

Put m= 68.5 kg, $r=3.43\times 10^{6} m$, $G=6.67\times 10^{-11} N m^{2} kg^{-2}$ and $M=6.43\times 10^{23} kg$ in the above expression.

$F=\frac{(6.67\times 10^{-11})(6.43\times 10^{23})(68.5)}{(3.43\times 10^{6})^{2}}$

F=249.82 N

Therefore, the correct answer is F=249.82 N.