Question

One rectangular solid with a square base has twice the height of another rectangular solid with a square base with the same side length. Which statements about the two rectangular solids are true? Check all that apply.
A) The bases are congruent.
B) The solids are similar.
C) The ratio of the volumes of the first solid to the second solid is 8:1.
D)The volume of the first solid is twice as much as the volume of the second solid.
E) If the dimensions of the second solid are x by x by h, the first solid has 4xh more
surface area than the second solid.

Answer 1

the answers are

the bases are congruent,

the volume of the first solid is twice as much as the volume of the second solid,

and

if the dimensions of the second solid are x by x by h, the first solid has 4xh more surface area than the second solid

(I just did this assignment)

Answer 2

Answer:

First rectangular solid and second Rectangular solid

1. Bases are in the form of square having same dimensions

2. Height of first rectangular solid=2 ×Height of second rectangular solid

The true statements are

A) The bases are congruent.→The meaning of term congruent is that , the two bases are in the shape of square having same dimensions.

(B) No, The solids are not similar.as ratio of side lengths in not same in each case , because the ratio of heights of two solid is equal to $\frac{1}{2}$.

(D) Volume of first solid = x *x*2 H=2 x²H

Volume of second solid = x*x*H=x²H

Ratio of volumes =2:1

So, option (D) is true.

(E) Surface area of first solid =2[x*x+x*2 H+2 H*x]

=2[x²+4 H*x]=2 *x*[x+4* H]

Surface area of second solid = 2[x*x+x* H+ H*x]=2[x²+2 H*x]=2* x*[x+ 2*H]

$S_{1}=S_{2}+4Hx$

Option A, D, E are correct about two solids.