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vladimir1956 [14]
3 years ago
13

In exercises 8-10, write a system of linear equations that has the ordered pair as its solution. (-6, -2)

Mathematics
1 answer:
Anika [276]3 years ago
5 0

Answer:

(8) x + y = -8 and 2x - y = -10

(9) 3x - y = -54 and 4x + y = -30

(10) x + y = 2 and x - y = 2

Step-by-step explanation:

Given [Missing from the question]

(8).\ (-6,-2)\ \\ (9).\ (-12,18)\ \\ (10).\ (2,0)

Required

Write a system of linear equations

The solutions to this question is open and have different solutions

Solving (8) (-6,-2)

Let the equations be: x + y and 2x - y

x + y = -6 - 2

x + y = -8 --- (1)

2x - y = 2 * (-6) - (-2)

2x - y = -10 -- (2)

So, the equations are:

x + y = -8 and 2x - y = -10

Solving (9) (-12, 18)

Let the equations be: 3x - y and 4x + y

3x - y = 3 *(-12) - 18

3x - y = -54

4x + y = 4 * (-12) + 18

4x + y = -30

So, the equations are:

3x - y = -54 and 4x + y = -30

Solving (9): (2,0)

Let the equations be: x + y and x - y

x + y = 2 + 0

x + y = 2

x - y = 2 - 0

x - y = 2

So, the equations are:

x + y = 2 and x - y = 2

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