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VLD [36.1K]
3 years ago
12

Write an explicit rule to represent the sequence: 20 24 28 32 36...

Mathematics
1 answer:
andrezito [222]3 years ago
7 0

Answer:

+4

Step-by-step explanation:

20+4=24

24+4=28

28+4=32

32+4=36

36-4=32

32-4=28

28-4=24

24-4=20

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DochEvi [55]

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4 0
3 years ago
If the circumference of a circle measures 3/4 π cm, what is the area of the circle in terms of π?
Vinil7 [7]
\bf \textit{circumference of a circle}\\\\
C=2\pi r~~
\begin{cases}
r=radius\\
-----\\
C=\frac{3\pi }{4}
\end{cases}\implies \cfrac{3\pi }{4}=2\pi r
\\\\\\
\cfrac{3\pi }{4(2\pi )}=r\implies 
\boxed{\cfrac{3}{8}=r}\\\\
-------------------------------\\\\
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A=\pi r^2\qquad \qquad \implies A=\pi \left( \boxed{\frac{3}{8}} \right)^2\implies A=\pi \left( \cfrac{3^2}{8^2} \right)
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5 0
4 years ago
If m∠WXY =160, what are m∠WXZ and m∠ZXY
Dominik [7]

Answer:

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x=13

4 0
3 years ago
Quadratics need help making parabola
timama [110]

Answer:

The equation of the parabola is y = \frac{1}{3}\cdot x^{2}-\frac{4}{3}\cdot x -4, whose real vertex is (x,y) = (2, -5.333), not (x,y) = (2, -5).

Step-by-step explanation:

A parabola is a second order polynomial. By Fundamental Theorem of Algebra we know that a second order polynomial can be formed when three distinct points are known. From statement we have the following information:

(x_{1}, y_{1}) = (-2, 0), (x_{2}, y_{2}) = (6, 0), (x_{3}, y_{3}) = (0, -4)

From definition of second order polynomial and the three points described above, we have the following system of linear equations:

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The solution of this system is: a = \frac{1}{3}, b = - \frac{4}{3}, c = -4. Hence, the equation of the parabola is y = \frac{1}{3}\cdot x^{2}-\frac{4}{3}\cdot x -4. Lastly, we must check if (x,y) = (2, -5) belongs to the function. If we know that x = 2, then the value of y is:

y = \frac{1}{3}\cdot (2)^{2}-\frac{4}{3}\cdot (2) - 4

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(x,y) = (2, -5) does not belong to the function, the real point is (x,y) = (2, -5.333).

5 0
3 years ago
Can anyone tell me the algorithm of Pi
Ray Of Light [21]

Answer:

representations are thought in the form utilized by Horner's method. E.g., in the decimal system we have

(1)√2= 1.41421 ... = 1 + 1/10 (4 + 1/10 (1 + 1/10 (4 + 1/10 (2 + 1/10 (1 + 1/10 ( ... )))))),π= 3.14159 ... = 3 + 1/10 (1 + 1/10 (4 + 1/10 (1 + 1/10 (5 + 1/10 (9 + 1/10 ( ... )))))),

But was there a positional system in which π was known? As S. Rabinowitz has realized, there indeed was such a system albeit an unusual one. The starting point was the series



which also can be written as



or, in the Horner form,



representations are thought in the form utilized by Horner's method. E.g., in the decimal system we have

(1)√2= 1.41421 ... = 1 + 1/10 (4 + 1/10 (1 + 1/10 (4 + 1/10 (2 + 1/10 (1 + 1/10 ( ... )))))),π= 3.14159 ... = 3 + 1/10 (1 + 1/10 (4 + 1/10 (1 + 1/10 (5 + 1/10 (9 + 1/10 ( ... )))))),

But was there a positional system in which π was known? As S. Rabinowitz has realized, there indeed was such a system albeit an unusual one. The starting point was the series



which also can be written as



or, in the Horner form,



3 0
3 years ago
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