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ElenaW [278]
3 years ago
12

What is the annual share of the profit awarded to the owner of a share of stock called?

Mathematics
1 answer:
madam [21]3 years ago
5 0
I think its common stock
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A mountain climber ascends 800 feet per hour from his original
navik [9.2K]

Answer:

4,800

Step-by-step explanation:

Just multiply 800 x 6, which gets 6,800. Then, get 11,600 and subtract 6,800 from it. You'll get 4,800.

7 0
3 years ago
3 1/7 + 4 3/14 = ?<br>plz help me ​
ale4655 [162]
Convert the mixed numbers to improper fractions, then find the LCD and combine.
Exact Form:
103/14
Decimal Form:
7.35714285
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7.35714285
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Mixed Number Form:
7 5/14
4 0
2 years ago
Eric and frank want to equally share 4/3 feet of rope. What length of rope should each friend get? Explain how to use a drawing
Pani-rosa [81]
I hope u can understand...

5 0
3 years ago
Read 2 more answers
For the love of God help me !! I'm desperate for it tomorrow
Eduardwww [97]
Try to relax.  Your desperation has surely progressed to the point where
you're unable to think clearly, and to agonize over it any further would only
cause you more pain and frustration.
I've never seen this kind of problem before.  But I arrived here in a calm state,
having just finished my dinner and spent a few minutes rubbing my dogs, and
I believe I've been able to crack the case.

Consider this:  (2)^a negative power = (1/2)^the same power but positive.

So: 
Whatever power (2) must be raised to, in order to reach some number 'N',
the same number 'N' can be reached by raising (1/2) to the same power
but negative.

What I just said in that paragraph was:  log₂ of(N) = <em>- </em>log(base 1/2) of (N) .
I think that's the big breakthrough here.
The rest is just turning the crank.

Now let's look at the problem:

log₂(x-1) + log(base 1/2) (x-2) = log₂(x)

Subtract  log₂(x)  from each side: 

log₂(x-1) - log₂(x) + log(base 1/2) (x-2) = 0

Subtract  log(base 1/2) (x-2)  from each side:

log₂(x-1) - log₂(x)  =  - log(base 1/2) (x-2)  Notice the negative on the right.

The left side is the same as  log₂[ (x-1)/x  ]

==> The right side is the same as  +log₂(x-2)

Now you have:  log₂[ (x-1)/x  ]  =  +log₂(x-2)

And that ugly [ log to the base of 1/2 ] is gone.

Take the antilog of each side:

(x-1)/x = x-2

Multiply each side by 'x' :  x - 1 = x² - 2x

Subtract (x-1) from each side:

x² - 2x - (x-1) = 0

x² - 3x + 1 = 0

Using the quadratic equation, the solutions to that are
x = 2.618
and
x = 0.382 .

I think you have to say that <em>x=2.618</em> is the solution to the original
log problem, and 0.382 has to be discarded, because there's an
(x-2) in the original problem, and (0.382 - 2) is negative, and
there's no such thing as the log of a negative number.


There,now.  Doesn't that feel better. 
 






4 0
3 years ago
Fred Salmon purchased six $1,000 bonds at 92. The bonds pay 6.5%, what is the cost of the bonds
soldi70 [24.7K]
The cost of the bond
6×1,000×0.92=5,520
4 0
3 years ago
Read 2 more answers
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