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2 years ago

Segment EF is the midsegment of trapezoid ABCD. Find the length of segment EF if segment AB is 20 and segment CD is 12.

Mathematics

2 answers:

Vika [28.1K]2 years ago

7 0

Midsegment = 1/2(base1 + base2)

EF = 1/2(AB + CD)

EF = 1/2(20 + 12)

EF = 1/2(32)

EF = 16

Answer

EF = 16

irakobra [83]2 years ago

3 0

Answer:

The length of the mid-segment EF is 16.

Step-by-step explanation:

In this exercise the main idea is to know the formula for the mid-segment of a trapezoid. This formula should be well known because it is used to find the area of a trapezoid.

If we denote the mid-segment of a trapezoid as $m$ , the larger basis as $B$ and the smaller basis as $b$ , the formula states:

$m = \frac{B+b}{2}.$

In this particular exercise $m=EF$ , $B=AB$ and $b=DC$ .

Thus,

$EF = \frac{DC + AB}{2} = \frac{20+12}{2} = \frac{32}{2} = 16.$

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Answer:

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Step(i):-

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