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Elodia [21]
3 years ago
12

I need to know if it is t or f

Mathematics
1 answer:
KatRina [158]3 years ago
3 0

Answer:

True

Step-by-step explanation:

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Can someone help me with this?
alexandr1967 [171]
N = 4 + x? i think, im not really sure but im pretty sure it is
3 0
3 years ago
The equation of a circle is given below. (x-0.5)^{2}+(y-3.5)^{2} = 16(x−0.5) 2 +(y−3.5) 2 =16left parenthesis, x, minus, 0, poin
Mashutka [201]

Answer:

<h2>The radius is 4 units long.</h2>

Step-by-step explanation:

The given equation is

(x-0.5)^{2} +(y-3.5)^{2} =16

This equation belongs to a circle, which center is at (0.5, 3.5) and its radius is 4.

You can deduct its elements, becase this equation of the circle is explicit, which means the constant term represents the square power of the radius. Solving that, we have

r^{2} = 16\\r=\sqrt{16}\\ r=4

Therefore, the radius is 4 units long.

3 0
3 years ago
Factors can be defined as ________ which divide the dividend without leaving any reminder​
Svetradugi [14.3K]

Answer:

Factors can be defined as a number or algebraic expression which divide the dividend without leaving any reminder.

7 0
3 years ago
Y=2x+3 <br> y=3x+1 <br> solve the system of equations using substitution
Lynna [10]

Answer:

(2, 7 )

Step-by-step explanation:

Given the 2 equations

y = 2x + 3 → (1)

y = 3x + 1 → (2)

Substitute y = 3x + 1 into (1)

3x + 1 = 2x + 3 ( subtract 2x from both sides )

x + 1 = 3 ( subtract 1 from both sides )

x = 2

Substitute x = 2 into either of the 2 equations for corresponding value of y

Substituting x = 2 into (1)

y = 2(2) + 3 = 4 + 3 = 7

Solution is (2, 7 )

4 0
3 years ago
Read 2 more answers
If x+y=8 and xy =15 find the value of x³+y³.​
alexgriva [62]

Answer:

<h2>152</h2>

Step-by-step explanation:

<h3>let x= 5 and y= 3</h3><h3 /><h3>x + y = 8</h3><h3>5 + 3 = 8</h3><h3 /><h3>xy = 15</h3><h3>5 × 3 = 15</h3><h3 /><h3>x³ + y³ = ?</h3><h3>5³ + 3³ = ?</h3><h3>125 + 27 = 152</h3>

\tt{ \green{P} \orange{s} \red{y} \blue{x} \pink{c} \purple{h} \green{i} e}

7 0
3 years ago
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