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Olenka [21]
3 years ago
6

Evaluate the expression under the given conditions. sin(θ − ϕ); tan(θ) = 4/3 , θ in Quadrant III, sin(ϕ) = − 10/10 , ϕ in Quadra

nt IV
Mathematics
2 answers:
g100num [7]3 years ago
6 0

Answer:

Step-by-step explanation:

ValentinkaMS [17]3 years ago
6 0

Answer: -0.6

Step-by-step explanation:

First thing to do is to solve for θ and ϕ from the given information

tan(θ) = 4/3,

θ = tan-¹4/3,

θ = 53.1°

Since tan is positive in quadrant III, θ = 53.1°

Also,

sin(ϕ) = − 10/10 ,

ϕ = sin-¹-1

ϕ = 270°

If ϕ is in the fourth quadrant, that gives 360 - ϕ i.e 360 - 270 = 90°

Substituting the values of θ and ϕ into sin(θ − ϕ), we have;

Sin(53.1 - 90)

= sin (-36.9°)

= -0.6

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3x - 2x + 4 = 5x - 4x - 8

First, let's focus on the left side of the problem (3x - 2x + 4). Let's subtract 3x - 2x which will get us 1, and since a variable by itself is considered 1, we can just put the variable.
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Third, we can now cancel out x on each side. This will leave us with 4 = -8, which is false, meaning that there is no solution to this problem.

\fbox {D) No Solution}
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