The 10 tons should have 37.9% cement.
Let the 25% mixture be x tons
Then the 68% mixture will be (10 -x) tons.
Using formula for mixtures:
Let p for percentage and w for weight in tons.
p₁w₁ + p₂w₂ = pw
25*x + 68*(10-x) = 37.9*10
25x + 680 - 68x = 379
680 - 43x = 379
680 - 379 = 43x
301 = 43x
43x = 301
x = 301/43
x = 7
Recall that x, was for the 25% mixture, 7 tons.
a) For the 68% mixture, = 10 - x = 10 -7 = 3 tons.
b) For the 25% mixture = x = 7 tons.
Answer:
295/2
Step-by-step explanation:
1760/12
885/6
295/2
Answer:
11.37 lb-ft
Step-by-step explanation:
We are given that
Force,F=3 pounds
![\theta=42^{\circ}](https://tex.z-dn.net/?f=%5Ctheta%3D42%5E%7B%5Ccirc%7D)
Let Point A (3,7) and point B(8,8)
We have to find the work done by the force.
![d==](https://tex.z-dn.net/?f=d%3D%3C%288-3%29%2B%288-7%29%3E%3D%3C5%2C1%3E)
feet
We know that Work done by the force
![W=Frcos\theta](https://tex.z-dn.net/?f=W%3DFrcos%5Ctheta)
Substitute the values
![W=3\times \sqrt{26}cos42=11.37 lb-ft](https://tex.z-dn.net/?f=W%3D3%5Ctimes%20%5Csqrt%7B26%7Dcos42%3D11.37%20lb-ft)
Hence, the work done by the force =11.37 lb-ft
Answer:
4) choice 1) 14.7 cm
5) choice 2) 14.8 cm
Step-by-step explanation:
4) 10^2 + 10^2 + 4^2 = 216
sq rt 216 = 14.7
5) 14^2 + 3^2 + 4^2 = 221
sq rt 221 = 14.86