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andrezito [222]

3 years ago

15

Solve for x: -3x + 4 = -8

2 answers:

andrew11 [14]3 years ago

6 0

Hi there, to solve this problem we have to do this, Add -4 on both sides, 4+-4+-3x=-8+-4. Now you should have, -3x=-12. Lastly, we divide each side by -3, which gives us x=4. Therefore, the answer is x=4. Hoped I helped. :)

Virty [35]3 years ago

4 0

- 3 x + 4 = - 8

subtract 4 from both sides :

- 3 x + 4 - 4 = - 8 - 4

- 3 x = - 12

Divide both sides by : - 3

- 3 x / 3 = - 12 / - 3

x = 12 / 3

x = 4

hope this helps!

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The Davis family drove a total of 587 miles, starting on Friday and ending on Sunday. They drove 182 miles on Friday and 260 mil

valina [46]

Answer:

145

Step-by-step explanation:

Because what you want to do is add 260 to 182 then subtract from 587. I hope that helped! :)

8 0

3 years ago

Find all solutions in the interval from [0,2pi)<br> 2cos(3x)= -sqrt{2}

algol [13]

Solutions of $2cos(3x)= -\sqrt{2}$ in the interval from [0,2pi) is $x =\frac{\pi}{12}$ and $x = \frac{23\pi}{12}$ .

<u>Step-by-step explanation:</u>

Find all solutions in the interval from [0,2pi)

$2cos(3x)= -\sqrt{2}$

⇒ $2cos(3x)= -\sqrt{2}$

⇒ $\frac{2cos(3x)}{2}= \frac{-\sqrt{2}}{2}$

⇒ $cos3x= \frac{-\sqrt{2}(\sqrt{2})}{2{\sqrt{2}}}$

⇒ $cos3x= \frac{-2}{2{\sqrt{2}}}$

⇒ $cos3x= \frac{-1}{{\sqrt{2}}}$

⇒ $cos^{-1}(cos3x)= cos^{-1}(\frac{-1}{{\sqrt{2}}})$

⇒ $3x=\pm \frac{\pi}{4}$

⇒ $x=\pm \frac{\pi}{12}$

Cosine General solution is :

$x = \pm cos^{-1}(y)+ 2k\pi$

⇒ $x = \pm \frac{\pi}{12}+ 2k\pi$ , k is any integer .

At k=0,

⇒ $x =\frac{\pi}{12}$ ,

At k=1,

⇒ $x = - \frac{\pi}{12}+ 2\pi$

⇒ $x = \frac{23\pi}{12}$

Therefore , Solutions of $2cos(3x)= -\sqrt{2}$ in the interval from [0,2pi) is $x =\frac{\pi}{12}$ and $x = \frac{23\pi}{12}$ .

5 0

3 years ago

Hello me again, answer this question, please show work

Rudik [331]

Answer:

6x

Explanation:

A number is x. 6 x x is written as 6x

8 0

3 years ago

Read 2 more answers

Help help pls pls pls

deff fn [24]

Answer:

x = 13.6 in

Step-by-step explanation:

The arc x is calculated as

x = circumference of circle × fraction of circle

= 2πr × $\frac{0.8}{2\pi }$ ( cancel the 2π on numerator/ denominator )

= 17 × 0.8

= 13.6 in

3 0

4 years ago

The half-life of a radioactive substance is 200 years. There are 8000 grams of the substance initially. How many grams of the su

STALIN [3.7K]

Answer:

There are 2,000 grams left after 300 years.

Step-by-step explanation:

Giving the following information:

The half-life of a radioactive substance is 200 years. There are 8000 grams of the substance initially.

<u>First, we need to calculate the reduction of the substance each year:</u>

Yearly reduction= 8,000/400= 20 grams per year

<u>Now, for 300 years:</u>

300 year reduction= 20*300= 6,000

There are 2,000 grams left after 300 years.

6 0

3 years ago