Answer:
- (b) Her scale model drawing will not fit on a piece of paper that is 8.5 inches by 7 inches because the dimensions are not proportional to the scale.
Explanation:
(a) What is the length of the garden in her model? Show your work, including your proportion
<u>1. Scale</u>:
- model length / real length = 1 inch / 2 feet
<u>2. Proportion</u>:
Naming x the model length:
- 1 inch / 2 feet = x / 6 feet
Cross multiply:
- 1 inch × 6 feet = 2 feet × x
Divide both sides by x:
- x = 1 inch × 6 feet / 2 feet = 3 inch.
Answer: 3 inches
(b) If the width is 5 inches for the scale model and the scale is still 1 inch to 2 feet, will her scale model drawing fit on a piece of paper that is 8.5 inches by 7 inches? Why or why not?
Both the width and the length must use the same scale, thus the corresponding sides of the scale model and the drawing must be proportional.
In the model the ratio of the length to the width is 3 inch / 5 inch
In the paper the ratio of the length to the width is 8.5 inch / 7 inch
Hence, you can see that in the model the length (mumerator of the fraction) is less than the width (denominator) while in the paper it is the opposite. Bieng the two ratios different, they are not proportional, and you conclude that her scale model drawing will not fit on a piece of paper that is 8.5 inches by 7 inches.
Answer:
-5x+5
Step-by-step explanation:
i just got this question
Answer:
30 students
Step-by-step explanation:
3 students = 10% of the class.
x students = 90% of the class.
(If more, less divides. Let x be the subject. Since we know 10% of the class already, we have to find the remaining 90% that is 100% - 10% = 90%.)
x = 90%/ 10% × 3 students. ( the percentage signs cancel out and so do the zero's.)
x= 9/1 × 3 students ( 9/1 is the same as 9)
x= 27 students
(To find the total, you must add the 10% of the students to the remaining 90% of the students in the class.)
Total number of students in the class = 27 students + 3 students
= 30 students
First, you should solve for

, which equals

. Now, solve the integral of

=

, to get that

. You can check this by taking the integral of what you got. Now by the Fundamental Theorem
![\int\limits^2_0 {4x} \, dx=[2x^2] ^{2}_{0}=2(2)^{2}-2(0)^2=8](https://tex.z-dn.net/?f=%20%5Cint%5Climits%5E2_0%20%7B4x%7D%20%5C%2C%20dx%3D%5B2x%5E2%5D%20%5E%7B2%7D_%7B0%7D%3D2%282%29%5E%7B2%7D-2%280%29%5E2%3D8)
.
This should be the answer to your question, if I understood what you were asking correctly.