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REY [17]
3 years ago
5

What percent of data set is represented in Q1

Mathematics
1 answer:
elena55 [62]3 years ago
4 0
It is 25% because it is 1/4 which is a quarter. 
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If it's 11:51 right now. what time will not be in 11 hours and 37 minutes ?
AfilCa [17]

Answer:

11:52...

Step-by-step explanation:

11:52. It could be any time except the time 11:37 from now, since its NOT going to be.

Hope this helps!

6 0
3 years ago
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Which comparison is true ?<br><br> 3/4 &gt; 7/8<br> 1/2 &lt; 5/8<br> 2/3 &lt; 3/8<br> 7/8 &gt; 9/10
Cloud [144]

Answer:

B

Step-by-step explanation:

3 0
3 years ago
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Select the correct answer.<br> Which graph shows a function and its inverse?
labwork [276]

Answer:

See below

Step-by-step explanation:

If a function is bijective and 1-to-1, then it will have an inverse function. Consequentially, they will be symmetrical about the line y=x, which is a diagonal line passing through the origin at a 45 degree angle.

None of the graphs look correct though, but it also seems that some options are cut out, so make sure to choose the correct graph given the characteristics I've previously described.

6 0
1 year ago
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Which figure is not a parallelogram?
lara31 [8.8K]

Answer:

the second one

Step-by-step explanation:

it does not say that both sides are parallel

3 0
3 years ago
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Assume that​ women's heights are normally distributed with a mean given by mu equals 62.5 in​,and a standard deviation given by
Misha Larkins [42]

Answer:

(a) 0.5899

(b) 0.9166

Step-by-step explanation:

Let X be the random variable that represents the height of a woman. Then, X is normally distributed with  

\mu = 62.5 in

\sigma = 2.2 in

the normal probability density function is given by  

f(x) = \frac{1}{\sqrt{2\pi}2.2}\exp{-\frac{(x-62.5)^{2}}{2(2.2)^{2}}}, then

(a) P(X < 63) = \int\limits_{-\infty}^{63}f(x) dx = 0.5899

   (in the R statistical programming language) pnorm(63, mean = 62.5, sd = 2.2)

(b) We are seeking P(\bar{X} < 63) where n = 37. \bar{X} is normally distributed with mean 62.5 in and standard deviation 2.2/\sqrt{37}. So, the probability density function is given by

g(x) = \frac{1}{\sqrt{2\pi}\frac{2.2}{\sqrt{37}}}\exp{-\frac{(x-62.5)^{2}}{2(2.2/\sqrt{37})^{2}}}, and

P(\bar{X} < 63) = \int\limits_{-\infty}^{63}g(x)dx = 0.9166

(in the R statistical programming language) pnorm(63, mean = 62.5, sd = 2.2/sqrt(37))

You can use a table from a book to find the probabilities or a programming language like the R statistical programming language.

4 0
3 years ago
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