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4 years ago

I need help on this please

Mathematics

2 answers:

Ipatiy [6.2K]4 years ago

4 0

I can not see the image you provided .

skad [1K]4 years ago

4 0

Your image is unclear, I cannot help you unless you upload a better one, sorry

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Can u pls answer this for me <br><br><br> 8+.0573+1.64=

Wittaler [7]

9.6973 will be your answer

5 0

3 years ago

Kirsten is driving to a city that is 275 miles away. When Kirsten left home, she had 10 gallons of gas in her car. Assume that h

Snowcat [4.5K]

Answer:

(a). Assuming consumption is only dependent upon miles driven, the function is defined as :

Amount of gas left after driving x miles :

$f(x)=10-\frac{x}{25}$

(b). The y-intercept is obviously 10. This represents the initial gas in the tank, 10 gallons.

(c). The x-intercept is the solution to

$0=10-\frac{x}{25}\\\\10=\frac{x}{25}\\\\\implies x=250$

The x-intercept is 250. It represents the "distance taken by car to empty the tank".

3 0

3 years ago

Jennifer is shopping with her mom. They pay 2 dollars per pound for tomatoes. What is the constant of proportionality in the sit

pantera1 [17]

2x=y where 2 is dollars per tomatoe, x is amount of pounds of tomatoes, and y is amount of money spent in total. say you got 3 pounds of tomatoes; the equation would be 2(3)=y. y=6. Hope I helped!

5 0

3 years ago

What is the period and midline?

OverLord2011 [107]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\
% function transformations for trigonometric functions
\begin{array}{rllll}
% left side templates
f(x)=&{{ A}}cos({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\

\end{array}\qquad$

$\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks}\\
\quad \textit{horizontally by amplitude } |{{ A}}|\\
\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\
\bullet \textit{vertical shift by }{{ D}}\\
\qquad if\ {{ D}}\textit{ is negative, downwards}\\
\qquad if\ {{ D}}\textit{ is positive, upwards}\\


\end{array}$

$\bf \begin{array}{llll}
\bullet \textit{function period}\\
\qquad \frac{2\pi }{{{ B}}}\ for\ cos(\theta),\ sin(\theta),\ sec(\theta),\ csc(\theta)\\
\qquad \frac{\pi }{{{ B}}}\ for\ tan(\theta),\ cot(\theta)
\end{array}
$

so if you notice yours $\bf \begin{array}{llll}
3.2cos&\left( \frac{5}{3}\theta \right)+&6.1\\
&\ \uparrow&\uparrow \\
&B&D 
\end{array}$

now.. normally the function $\bf 3.2cos&\left( \frac{5}{3}\theta \right)$
has a D value of 0, or no vertical shift, and the amplitude and the period simply make the wave taller and thinner, but the midline is still the x-axis

now, with D = 6.1, that moves the midline up vertically that much

now.. the period, well, B = 5/3, normal period of cosine is $2\pi$
so, the new period will be $\bf \cfrac{2\pi }{B}\implies \cfrac{2\pi }{\frac{5}{3}}\implies \cfrac{6\pi }{5}$

notice the picture below
the vertical shift by the D component, or 6.1, moved the midline to y = 6.1 :)

6 0

3 years ago

The figure shows a blueprint of a dining room, kitchen, and living room. Each square has a side length of 1/4 inch. Hardwood flo

scoray [572]

Answer:

there is no attachment

Step-by-step explanation:

6 0

4 years ago

Read 2 more answers