3 years ago

I need help on this please

Mathematics

2 answers:

Ipatiy [6.2K]3 years ago

4 0

I can not see the image you provided .

skad [1K]3 years ago

4 0

Your image is unclear, I cannot help you unless you upload a better one, sorry

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Step-by-step explanation:

To solve the problem, we divide the whole expression by 2:

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→ x^2 + 5x + 4 < 0

Factorizing

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The expression is ONLY negative when:

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Therefore, the solution is:

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Yuri thinks that 3/4 is a root of the following function. q(x) = 6x3 + 19x2 – 15x – 28 Explain to Yuri why 3/4 cannot be a root.

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Answer:

Yuri is not correct.

Step-by-step explanation:

Given expression is q(x) = 6x³ + 19x² - 15x - 28

If 'a' is a root of the given function, then by substituting x = a in the expression, q(a) = 0

Similarly, for x = $\frac{3}{4}$ ,

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= $6(\frac{27}{64})+19(\frac{9}{16})-15(\frac{3}{4})-28$

= $(\frac{162}{64})+(\frac{171}{16})-(\frac{45}{4})-28$

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= $-\frac{1666}{64}$

= $-\frac{833}{32}$ ≠ 0

Therefore, Yuri is not correct. x = $\frac{3}{4}$ can not be a root of the given expression.

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